EQUAÇÃO DO 2º GRAU INCOMPLETA SEM FÓRMULA \Prof. Gis/

Did you know that it is possible to solve a quadratic and incomplete equation, okay, without using the Báskara solving formula, which is much simpler, right guys, so take a look, see that here I have a quadratic equation because it was characterized by a quadratic equation because the greatest exponent of X is two and see what I have here that it is an equation because it is equal to 0 but so you remember what a quadratic equation looks like. It looks like this here we have the reduced form of the quadratic equation. I have a coefficient that is on the side of x squared, coefficient A will always be on the side of x squared, so mark this well, coefficient B will always be on the side of X and coefficient C will be the one that is alone, He doesn't accompany anyone, okay?

So let's identify in this quadratic equation who the coefficients AB and C are, see that here the coefficient A is how many people don't have any number here on the side of x squared so it is equal to one and the coefficient B that that guy who is on the side of coefficients for you to remember so that you can identify in a quadratic equation what these coefficients are. So let's get to the point, how do I solve a quadratic equation without using the Baskara formula? Let's do the practical process so I'm going to take x squared and this 25 which is minus here I'm going to put this 25 on the second member so when I change sides of Equality it changes sign and does the inverse operation so it will pass as being plus 25, look what I'm doing guys, it was minus 25, go here plus 25 so x squared = 25 now it's simple for you to find out the value of X because solving a quadratic equation means finding the value of x that satisfies our sentence here so think here with me.

What number do I square to 25? Could it be which could be in five very well plus a quadratic equation it only has one root? a result?

root means result, okay folks, not a quadratic equation there is a maximum of two, at most there can be one, but there can be a maximum of two, so five satisfies Ok, but there is one more root here in this case which is minus 5, because Think with me, if I do - 5 squared minus 5 squared It will result in more than 25, right? Because of the sign rule then it results in more 25 and if I do 5 squared it will also be more than 25, so the roots of this equation are negative five so we say the number I square takes 25, no people, a quick way to do it is to take and take the square root of this number here, So you go there and do what is the square root of 25 and the square root of 25, I know that in this context when applied to the equation it can be the value of positive five and the value of negative five. So for ours we put it like this, about five and look how quick it is to do, of course it took me a while because I'm explaining everything step by step to you, but now you get the hang of it, you can do it here in less than a minute, right?

You need to know the concept of square root because otherwise you won't be able to solve it easily, so I managed to find the two roots of the equation, so let's do another example here to practice a little. Remembering that here the coefficient A is not equal to this one, here it was one who is the coefficient A here the coefficient A is three but it will make a little difference. So let's do this one directly without removing the coefficients because I already know that it is an incomplete quadratic equation just by looking at it because you can see that there is the guy who is on the side of x squared and there is that guy who is alone which would be our independent term so also in this equation our B will be equal to zero so it is an incomplete equation, and how can I easy to solve firstly I'm going to take this value here which is - 48 I'm going to put it on the other side of Equality on the second member then it will be 48 positive it was less it came more talking about the trick, right guys, a practical way to do this three now he is multiplying x squared isn't it so it will be like x squared = 48 / 3 I did the inverse operation so then I will get x squared = 48 / 3 we will get 16 and how do I finish this calculation even at I finish this calculation by taking the square root of the 16 that I have here, right, because I think what number do I take the square that gives 16?

Just taking the square root of 16 and taking the square root of 16 we will then obtain the results of o or less which is the value even very well the value of four. So it means that in this situation here the values ​​of x that satisfy this sentence are four positive and four negative so I solved my quadratic equation quickly and then when you solve a quadratic equation you put the solution set and the solution set we We put them in ascending order from smallest to largest. So in this case I would put, oh, I'm going to put it up here, it's S = S of solution set because I managed to solve it, right, it will be negative five and positive five so mark it, I did it very tightly here, right, for you to mark it and also and in this other one case solution set that A would be my answer will be minus four, and look, wanting to put 5 here the same as I put it here oh oh, minus 4 and plus four I put the solution set I solved the quadratic equation and I didn't use Bhaskara's solving formula .

So remember , in these cases where I take the square root at the end, which coefficient is missing? It's when the B coefficient is missing and don't miss the next class where I'll explain how to solve a quadratic equation when the C coefficient is missing. Also, don't forget to subscribe to the Gis channel, give this super top class a thumbs up, right guys?

Here's a quick tip to make sure you don't pay too much attention to solving this quadratic equation. And I'll see you in the next class bye. .

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