Optical Isomerism | Detailed Marathon | NEET 2024 | NEET Conquer Batch | HSP

very good evening Almighty twins how is everyone welcome to all of you to yours and Academy neet English Channel it gets today we are going to start with the awesome topic what's the name of the topic you know from the thumbnail yes that's Optical isomers if I talk about opticalized with a number of things are there which you don't know if I say that okay let me tell you each and everything one by one but before that everyone do let me know can you hear me can you see me if yes you know the drill

hello very good evening very good evening very good evening to Priyanka veg Journey Apple ramakant my all dear friends I welcome to all of you to this fabulous awesome topic that holds a whole lot of weightage in your organic chemistry not only in organic chemistry it is also very very important in your inorganic chemistry if I talk about coordination chemistry this chapter holds a lot of weightage so if we know about Optical ISO in number of things we are going to cover it up so it's really very very important so how is everyone introduction of

ice in the starting I have explained structural isomerism and geometrical isomerism two topics in detail I have already told you if you see the previous lectures isomerism I have told you but yes introduction of isomerism I will tell you today but let me tell you that Optical isomerism is really very very important and number of things are there which you actually don't know and number of times you are going to get wrong answer before I start I want to see in the chat section green signal the fire Prema killer science everyone is here so before

I start this awesome chapter I want to see some Josh in the chat section Muhammad ramzan everyone is here I want to see some shows in the chat section for your HSV Baba I have been teaching for last 23 plus years and produced number of ranks top 10 all the ranks you can say in Mass selection so kids today yes the most awaited topic on everyone's demand I'm going to start yeah I've seen arthi is there the sharing is there everyone it says so let me start if you're new to this channel subscribe this channel

and others hit the like buttons likes are very very less it's yours Channel kids what are you doing it's yours own channel hit the like buttons and show me your presence I need attendance you know wherever you are in school one two three four so ramu yes present Shamu yes present that attendance everyone Mark that attendance yes so let me start if I talk about Optical isomerism gets Optical isomerism this Optical isometer is really very very important and if I ask one question it's for optical isomerism what is the necessary condition is there anyone who

is going to let me know what is the one and only one necessary condition for a compound to be optically active yes this is my question to each and everyone and let me know necessary condition that see who is going to give me the answer necessary condition for a compound to be optically active for a compound to be optically active yes I want to see in the chat section I want to see this chat section the answer chiral carbon chiral Center everyone is writing chiral carbon chiral Center so kids let me tell you answer of

this question chiral carbon is not the necessary condition chiral carbon if your ulcer is chiral carbon then examiner will give you zero marks gets this is not the necessary condition if you are writing chiral carbon is the necessary condition your examiner will give you zero marks zero marks this is not the necessary condition now you will say sir what is this you are saying that chiral carbon is not the necessary condition yes chiral carbon is not the necessary condition if you're writing this thing your examiner will give you zero marks so what is the necessary

condition let me tell you and that's why this lecture is very very important for each and every one so what a compound to be optically active for a compound to be optically active compound should not have element of symmetry that is plane of symmetry and center of symmetry compound should not have compound should not have compound shouldn't have pause and cause pause and cos compound should not have pause and cause shouldn't have pause and cause should not be present that means neither plane of symmetry nor centroximetry compound can have chiral carbon or cannot have chiral

carbon but that is not the necessary condition compound should not have plane or Symmetry and center of symmetry if compound is not having plane of symmetry and center of symmetry then also the compound can be optically active so what are you talking about yes I'm absolutely correct let me tell you this is the thing which I am going to tell you kids if I say if I say a compound is having a compound is having chiral carbon having chiral carbons having chiral carbons what I have written a compound is having chiral carbons underline it underline

it a compound is having chiral carbons but this compound is not having but if this compound not having not having what not having pause and pause pause and cause then what do you say it's a compound is having chiral carbons but if this compound it's not having if this compound is not having pause and cause then what will you say this compound is optically active or optically inactive what will you say what will you say this compound is optically active or inactive definitely this compound this compound will be optically active this compound will be optically

active optically active now question arises question arises how to find out plane of symmetry and center of symmetry it's let me tell you plane of symmetries 99 percent important for neet examination but Center of symmetry is very very less important so are you ready so are you ready for plane of symmetry and center of symmetry what I said plane of symmetries importance is 99 important because we should know we should know very well that what is important and what is not important just getting knowledge is not everything we should have to get the rank best

strength so remember that plane of symmetry is 99 important and Center of symmetry for your examination and just one percent important so where you have to focus more which point you have to focus more where you have to put your maximum Focus plane of symmetry so this is the thing which is very very important for your examination so we have to understand plane of symmetry everyone yuvarajan good evening good evening good evening good evening so everyone hit the like button so are you ready no kids if you want to get 100 marks then you have

to understand plane of symmetry in detail if you want to get command in coordination chemistry that is a portion of inonic chemistry then you have to understand plane of symmetry so is everyone ready for plane of symmetry now let's see what is Plano symmetry let me tell you what is this plane of symmetry let me write down the definition of plane of symmetry plane of symmetry plane of symmetry is an imaginary plane is an imaginary plane is an imaginary plane which divides the whole compound which divides the whole compound and two equal parts in to

equal parts so that so that one part to that one part is the exact is the exact Mirror Image mirror image of second part now kids let me give you some examples of it but before that do let me know everyone you just take your hand either right hand or left hand so better to take your right hand okay and you you're not supposed to cut it don't take knife and start cutting no imaginary plain see it is an imaginary plane imagine just you have to imagine right imaginary plane so just try to imagine from

where you have to cut it so that it could divide into equal parts is there any way either you cut from here this side is the thumb and that side thumb is not there see you cut it like this you won't be able to divide in two equal parts and if you divide it like this then this is the rough surface and this is the smooth surface you won't be able to divide this ant is it it Vidya pravalika so is there any special session for isomerism I have taken um isomerism structural isomerism I took

geometrical isomerism and this is the most important topic that is Optical isomism later later on you can see that you can watch that okay you can watch that later on right now so this hand is optically active right now let me draw over here and let me tell you see if I draw if I draw this a if I draw this a do let me know do let me know everyone if I draw this a is there any plane of symmetry is there any plane of symmetry do let me know everyone is there plane of

symmetry yes answer is yes there is plane of symmetry which one this is the plane of symmetry you can see this is known as vertical plane oximetry this if I divide from here this line is dividing this part and this part this part is just the mirror image of that part so this is known as vertical plane of symmetry everyone this is known as vertical plane oximetry so this compound can't be optically active now suppose if I draw this compound do let me know everyone is this compound having plane of symmetry do let me know

is this compound having plane of symmetry everyone do let me know is this compound having plane of symmetry yes the answer is yes if I divide it from here this is known as horizontal plane of symmetry this is known as horizontal symmetry horizontal plane of symmetry so these two compounds are optically inactive because they are having plain of symmetry these two compounds are having plane of symmetry so these two compounds are what optically inactive now you will say and you will ask sir these are ABCD don't tell us in this just let us know in

organic compound take an example of organic compound let me take example of organic compound same if I take these examples c h o ch3cl 2cl2 and see chlorine chlorine bromine iodine so how many compounds one two three four I took four compounds one two three four now if your visualization is very good you can do anything kids you can do you can understand anything so let's visualize it you won't be able to visualize it like this let me take four pens let me take help of four pens let me bring it just give me 30

seconds let me bring it okay 30 seconds just give me 30 seconds foreign so if I take this black this black one two three and four black let us suppose if I am going to draw CH4 CH4 so the C this carbon is holding four hydrogen atoms tetrahedral tetrahedrally okay now see this is carbon let us suppose carbon and if I draw this angle this is 90 degree so let me make it like this let us suppose this is 109 degree okay 1V as you visualize tetrahedral a visualization will give you the best command on

the stereochemistry this is one V right carbon one hydrogen another hydrogen two hydrogen atoms now let us suppose this another V is bisecting this V this V is bisected by this V you can see these two hydrogens can you see this is the structure given by Lee won't fall you must have studied in class ninth leave on top like this actually it is like this can you see or you can see like this you can visualize it like this whatever the way you want to visualize you can visualize now see if I am keeping it

like this that all are being hydrogens all the four atoms are same right all the atoms are same and if you divide it like this C if you divide it like this from that side let me bring near to you and if you divide it like from here the pen half of the pen will go towards right hand side half of the pen will go left hand side as the hydrogen atoms are spherical you can see now once you are going to come over here this is also hydrogen on right hand side and this is

also hydrogen on left hand side and this is once again hydrogen can you see this is plane of symmetry if you are going to bisect it you are getting the plane of symmetry everyone do let me know can you see the plane of symmetry is there so all the four atoms are same the plane of symmetry is there just to mean do let me know by the thumbs up that if everyone is able to understand because otherwise the difficulty will uh means increasing right do let me know that everyone is able to understand just show

me the thumbs up so now let me take the example of methyl chloride three atoms are same one atom is being different let me change let me change one atom this is chlorine one atom is being different so I have changed just one atom rest of the three atoms are remaining same I've just changed one atom you can see this atom has been changed can you see now if I divide just apply your brain everyone apply your brain let me check it out whether your mind is working or not brain is working or not if

I cut it like this this green pen will go half on the right hand side and hop on the left hand side this is hydrogen this is hydrogen and this is once again hydrogen so it is also having plane of symmetry so everyone is able to understand that this compound is having plane of symmetry here plane of symmetry is present in this plane of symmetry is present so these two are optically inactive now this is having two hydrogen two chlorines so two atoms are different let me change this atom also so let us suppose this

these two so these two are hydrogen atoms these two are same hydrogen atoms and these two are chlorine atoms just see these are being two chlorine atoms so let me put chlorine here let me put chlorine over here see now apply your brain again again I am not going to tell you if again and again I am going to tell you you won't be able to understand kids do let me know if you cut it from here the blue half portion will go on the right hand side and half portion will go on the left

hand side now this this carbon in the middle oh half on the right hand side half on the left hand side this hydrogen is already on the right hand side and left hand side and this is also chlorine right hand side left hand side is the plane of symmetry present or not in this so you can see here also plane of symmetry is present plane of symmetry is present now let's see the fourth atom everyone is ready for the fourth atom that all the four atoms are different fluorine chlorine bromine iron this carbon is holding

all four different atoms now see if I change color of all four so see this is white this is black this is blue and let me change the color of this pen also this is being green this has been green can you see all pore atoms are totally different okay CCC of or totally different everyone now if I make this V with black and white this is black and white and this is green coming towards your side and this blue is coming toward this side you can see 3D in the 3D figure this is being

carbon attached with four different atoms so group just see to it everyone see to it now you cut this green oh half of the green has gone right inside half of the green has gone left inside wow so nice now once you are coming to carbon carbon half will go on the right hand side half left hand side but there is white here is black they are different so no plane of symmetric it's C here the plane of symmetry is not present because there is white there is black here it was presents the green and

blue now you will say sir let me do one thing I will start cutting like this I will start cutting like this the white was the problem it was creating the problem half of the white will go toward this side half will come towards this side and black half that side this side but see this side is green and here is blue once again the plane of symmetry is not there you just see to it if you're going to cut it from here that half of the white will come towards this side half will go

toward that side and we're coming the middle area the plane of symmetry but this is green and this is blue the plane of symmetry is not present can you see kids wherever you want to cut you you you will say let's see sir this blue was creating problem let's cut it from here the blue half will go toward that side blue Hub will come towards this side but see that side is green and this side you can see is black so black is there can you see everyone are you able to visualize so I think

everyone got it that if any compound if any compound is having one carbon only one carbon attached with four different atoms or group if the compound is having if compound is having only one chiral carbon chiral carbon what is chiral carbon what is chiral carbon I will let you know but let me complete this if compound is having only one Coral carbon then no pause no cause that compound will not have pause and pause no pause no cause and compound will always be optically active compound will always be optically active compound well always be optically

active now so I'm going to tell you what is chiral carbon but before that one question must be arising to your brain that's a earlier you said that chiral carbon is not the necessary condition for a compound to be optically active now once you said that thing and you are talking about chiral carbon only see I will let you know what's the difference in the the concept C first let me tell you yep if carbon is attached carbon is attached with four different atoms or groups four different atoms or groups these four atom four different

atoms or groups should be according to CIP rule four different atoms or groups must be according to CIP roon according to CIP rule according to CIP rule if carbon is attached with four different atoms or groups according to CIP rule then then carbon is known as then carbon is known as chiral carbon chiral carbon chiral carbon or chiral carbon or chiral carbon or asymmetric carbon or asymmetric carbon now when the compound is having just one chiral carbon one chiral carbon let me tell you these statements may come as assertion and reasoning these are the killer

points where students are getting negative marks secrets if compound a compound is having just one chiral carbon just one chiral carbon it will never have pause cause it will never have pause and cross and it will always be Optical active will always be optically active and will always be optically active and that's why that's why in your examination you must have studied if I talk about examination that's a class 11th and 12th you have been taught only about chiral carbon and all the questions you are getting full marks because up to class 11 12 if

any teachers just talking about one chiral carbon so one carbon carbon then the compound will always be optically active because it will never have pause and costs but what I would like to say you are going to prepare for complete exam you are going to get more than 700 Mark 600 marks so you should know if compound is having more than one chiral carbon more than one Coral carbons then two possibilities are there then two possibilities are there kids two possibilities are there what are these two possibilities if compound is having pause cause either cause

or cause compound is having pause or cause or both then compound will be declared as optically inactive then compound will be optically inactive and second condition if I talk about second condition if compound is compound is neither having pause neither having pause nor cause nor cause then the compound will be optically active then the compound will be optically active so what is important thing then compound will be optically active now skits are you okay or you started feeling headache because these are the genuine points what I want to say that if any compound is having

what plane of symmetry or set of symmetry then the compound can never be optically active so is it possible that compound should have pause cost without chiral carbon yes let me tell you there are number of compounds gets their number of compounds there are number of I will not write like this otherwise you will say no there are number of um compounds which do not have chiral carbon which do not have any chiral carbon any chiral carbon the number of compounds which do not have any chiral carbon but they are optically active but they are

optically active now what's the reason this is the assets and this assertion is absolutely true 100 correct now there are number of compounds which do not have any caral carbon let me underline it what to be noted my Lord which do not have any chiral carbon the number of compounds we do not have any chiral carbon but they are optically active this statement is true or false everyone will say false or 99 people will say false but this is absolutely true 100 this is true and the reason is let us suppose this is the assets

in this assertion is 100 percent true the reason is what's the reason for it reason is because they do not have because they don't have plain of symmetry and center of symmetry this is the reason so what is important chiral carbon is important or plane of symmetry scent of symmetry this is important so remember that now I'm going to deal with another term now kids you must be thinking like that so we when we have studied on different YouTube channels we are thinking like that we will move like this and that gets this is a

hard Pro I'm not going to move like in that way so that you should get number of things misconceptions you will feel easy in that way but you won't be able to get command just to let me know everyone able to understand now let me tell you one more thing important thing compounds foreign don't have pause and pause pause and cause are known as are known as ymmetric compounds asymmetric compounds they are also known as T symmetric compounds D symmetric compounds and let me tell you they are also known as chiral compounds they are also

known as chiral compounds chiral compounds now kids try to understand this point this holds a lot of weightage what is this who is chiral carbon a carbon which is attached with four different atoms or groups is known as chiral carbon but who is chiral compound so what do you think chiral carbon and chiral compounds are same no not at all no way chiral carbon and chiral compounds they are totally different let me tell you let me tell you a chiral compound a compound can be current a compound can be current with or without chiral carbon

with or without chiral carbon see the statement the statement holds a whole lot of weightage the really those students those who don't know anything even the ABCD they will say what the lecture is what type of lecture it is but those who are having knowledge or those who want to gain knowledge actual knowledge really it holds a whole lot of weightage what I'm writing a compound can be Carol with or without Carol carbon this line is indicating one line is indicating the whole hardcore of optical ISO in this line is very very important gets very

very important a compound can be carried with or without chiral carbon so chiral carbon is one thing and compound spiralities another thing that means chiral carbon is not the necessary condition for a compound to be current sorry you got it now got it now let me tell you about the plane of symmetry see everyone see so let's do some questions let's do some questions but before doing those questions if I'm going to deal with chiral carbon I must have to tell you CIP rule because number of students will be there those who don't know anything

about CIP rule so but before moving towards CIP room let me tell you kids let me tell you the plane of symmetry in cyclic compound C this is a cyclic compound do let me know is this compound this is cyclobutane is this compound having any plane of symmetry answer is yes this compound is having plane of symmetry if I divide this compound like this this is vertical plane of symmetry if I divide this compound like this it is having horizontal plane of symmetry and if I divide this compound like this if I divide this compound

like this this is diagonal plane of symmetries it is having number of plane of symmetry so before moving ahead we should understand what is vertical plane of symmetry horizontal plane of symmetry and center of symmetry this is horizontal plane of symmetry horizontal pause what is horizontal plane of symmetry if I take one box let us suppose if I take this cup and if I cut it like this see if I cut it like this so this is vertical plane oximeter you can see this is vertical plane of symmetry this is this is vertical plane of

symmetry vertical plane of symmetry this is horizontal let me tell you horizontal plane of symmetry weight if I take this mobile if I take this mobile and if I cut it like this right horizontal plane of symmetry and this is diagonal plane of symmetry diagonal plane of symmetry diagonal plane of symmetry everyone are you able to understand diagonal brain of symmetry that means if I cut this board suppose this board is on that side also same then this is vertical plane of symmetry Oriental plane of 70 and diagonal plane of symmetry is everyone able to

understand is everyone able to understand no secrets everyone see let me tell you with the example otherwise you won't be able to understand secrets if I take this box if I take this box you see this box now if I cut it like this vertical plane of symmetry vertical plane of symmetry if I cut it like this see if I cut it like this horizontal plane of symmetry and if I cut it like this see cut it like this diagonal plane of symmetry you see this is being ncert it is like this if I cut

it like this this is diagonal plane of 70 can you see diagonal plane of symmetry diagonal diagonal plane of symptom can you see diagonally everyone now see if I draw one compound if I draw one compound see everyone C to it if I draw this compound it's this compound having plane of symmetry yes this compound is having plane of symmetry and the same compound if I am going to draw over here the same compound if I draw over here and just try to understand kids if I place here something like this and if I write

down here chlorine atom and here also chlorine atom hydrogen hydrogen atom now do let me know everyone is this compound having plane of symmetry do let me know if you are able to understand do let me know that yes sir this compound is having any plane of symmetry everyone do let me know kids if you are able to understand do let me know if this compound having plane of symmetry this is chlorine this is hydrogen this is chlorine and this is hydrogen atom see everyone do let me know are you able to understand is this

compound having plane of symmetry yes this compound is having plane of symmetry what type of plane of simply do let me know everyone everyone do let me know everyone do let me know which plate of symmetry if you are able to understand do let me know which plane of symmetry vertical no Priyanka vertical not vertical it is having diagonal plane of symmetry C it is having diagonal plane of symmetry if you have to if you are going to cut it like this if you are going to cut it like this this compound is having diagonal

plane of symmetry C this compound is having diagonal plane of symmetry if you cut it in this way then two equal parts it will be going to divide diagonal plane of symmetry is having it is having diagonal plane of symmetry diagonal brain of symmetry so this compound can't be optically active let me draw another compound C to it everyone see to it I am going to draw another compound cl cl what do you think this compound is having pain of symmetry do let me know everyone is this compound having plane of symmetry this compound is

just like this either you can draw it like this or you can draw it like this both the weight is the same compound you can draw it like that you can draw it like this both the compounds are being same or you can draw it like this also even you can draw it like this also all the compounds are being same all the compounds are being same you can draw it like this also all these are being same chlorine chlorine hydrogen hydrogen two let me know all three compounds are identical all three are identical what

type of plane of symmetry is there so definitely you can cut it like this in this compound I will say vertical plane of symmetry yes it is having vertical plane of symmetry your answer is absolutely correct this compound is having vertical plane of symmetry this compound is also having vertical plane of symmetry and this compound is having horizontal plane of symmetry so all three compounds are having plane of symmetry I hope that everyone is able to understand that all these compounds are having plane of symmetry so they are optically inactive plane of symmetry is present

so they are optically inactive inactive now this was the visualization way now let's come to the theoretical way are you ready everyone two chlorine atoms yes two chlorine atoms are there definitely two chlorine atoms are there and okay this is wrong just by chance so let me wrap it this should be hydrogen thank you thank you it should be a hydrogen thank you no secrets let me give you one well-known example that you know very well this compound this compound is known as tartric acid this compound is known as tartric acid just see to it

this is known as tartric acid tartric acid h o h o h o h c o o h you must have heard the name have you heard the name tartric acid the compound's name is tartric acid now if you don't know CIP rule let me tell you this compound is having two carbons this compound is having two chiral carbons this is one chiral carbon because right now you do not know what a chiral carbon sword is CIP rule I am going to let you know what is CIP rule just wait this is having two chiral

carbons but along with two chiral carbons you can see very well this compound is having what this compound is having bought this compound is having its plane of symmetry you can see very well that this compound is having plane of symmetry this plane of symmetry is dividing the whole compound in two equal parts just see to it this plane of symmetry is dividing the whole compound in two equal parts that this compound has been divided in two equal parts gets can you see and do let me know everyone if you can see that this compound

is divided in two equal parts so this is having plane of symmetry in spite of having although it was having two chiral carbons but due to this plane of symmetry this is optically inactive compound the Star Trek asset tartric acid is having two chiral carbons is having two chiral carbons but that also it is optically inactive but then also it is optically inactive what's the reason but then also it is optically an active why why kids this compound is having this tartaric acid is having two caral carbons but although it is having two carbon carbons

it is optically inactive what's the reason plane of symmetry is present so reason acids and reason reason is being plain of symmetry plane of symmetry is present and that's why this compound has been declared to be optically inactive now let me tell you CIP Rule and then we are going to find out iron carbon so everyone ready for CIP rule let's understand CIP root so everyone ready for CIP rule do let me know that everyone is ready for CIP rule p i p rule this is very very important the CIP rule is important for geometrical

isomerism as well as Optical isomerism very good now see kids C stands for one scientist name one scientist name this is also one scientist name and this is also one scientist name C stands for Kahan scientist it's the name I for in Gold oh my God what's her name in gold in gold and P4 before log pre-log fantastic name three scientists these are three scientists but no need to cram these names just remember CIP rule CIP rule so what is this CIP rule this is not simple rule this is gets really fantastic rule is everyone

really interested in the CIP rule see CIP rule number one CIP rule number one CIP rule number one so I'm going to deal with CIP rule number one the element the element the atom now question arises atoms should be present alone or the part of group so this atom can be allowed or the part of group the atom alone or art of group alone or part of group the atom hello what is the spelling of alone this is wrong a-l-o-n-e alone alone the atom alone or part of group which is directly attached with the chiral

carbon which is directly attached with chiral carbon with chiral carbon so we have to focus on which which atom the atom which is directly directly attached to the chiral carbon directly attached to the girl carbon with maximum atomic number with maximum atomic number will be senior most will be senior most senior most so seniority we have to find out now one question arises so we don't know atomic number then how to do it let me tell you no need to cram the atomic number let me tell you see you know very well one thing that

chlorine chlorine bromine iodine acetylene levastatin has been moved down the group atomic number increases or decreases do let me know in the chat section atomic number increases or decreases do let me know everyone be quick in the chat section everyone atomic number increases or decreases definitely atomic number increases increases right and as we move from left to right for example if I say a hydrogen hydrogen carbon nitrogen oxygen chlorine like that so atomic number will increase or decrease let me write down in one line if I write hydrogen carbon nitrogen oxygen fluorine the atomic number

will increase or decrease do let me know atomic number will increase so atomic number will increase definitely atomic number is going to increase so what I am saying no need to cram the atomic number this is just giving an idea about it what's the atomic number now see if I say if I say one carbon is over here and it is attached with one hydrogen okay one chlorine okay one bromine okay one iodine so this carbon is being chiral or not answer is yes so this carbon is declared to be chiral this is chiral why

chiral because all the four atoms are different so this is Karen this is very simple question this is very easy but if I say if I say I have taken one more carbon this is attached with ch2oh ch3 H2 ch3 and ch2i now what will you say this carbon is chiral yes this carbon is also current but so how it is chiral it should not be it's not expected to be current why see you will say this is carbon this is also carbon this is also carbon this is also carbon all powerful are being carbon

but gets if first atom is not able to decide the seniority if first atom is not able to decide seniority then see the second atom with second atom the topmost atom then see the top most second atom for seniority no C its carbon's topmost atom attached to oxygen this is carbon's topmost hydrogen and this carbon stop most is carbon and this carbon stop most it is iodine so who is senior most because all the carbons they are same Cherry baby hello please help me what's your question if this is which class number of isomer it's

this is after geometrical isolate first structural isomer in field geometrical and after geometrical this is Optical ISO in Cherry baby now see this is we have to see here iodine this iodine is different this oxygen is being different this hydrogen is being different and this carbon is being different so this carbon is also chiral carbon and let me write down this is CIP rule number two so let me tell you CIP rule number two what is CIP rule number two kids pip rule number two what's that what's that if first atom is not able to

decide if first atom if first atom is not able to decide seniority order seniority order then see the then C the second atom CD second topmost atom for seniority gets are you able to understand a first atom is not able to decide then see the second atom I hope that everyone is able to understand now for this this one let me tell you let me give you one example and do let me know everyone is this chiral carbon carbon attached with iodine ch2 iodine ch2 br what do you think is this carbon Chiron do let

me know in the chat section I'm waiting for your answer is this chiral carbon the yellow one is chiral Carbon rudra High HSP sir it's rudra from Ames rishikes oh my God welcome rudra yadav how you got this channel oh my God thanks it's really fantastic that's I'm really feeling happy to see you over here and that's why I'm each and everyone this is the best platform where we can meet and this is not having any boundaries fantastic fantastic now do let me know everyone is this compound having chiral carbon Priyanka is saying no this

is not caral carbon rest of other students do let me know is this carbon Chiron hey everyone where the energy level has gone what are you doing what's going on what's wrong with you there's only one answer have got that is from Priyanka and Priyanka is saying no this is rest of other students I want to see also from you no is also writing no gets I can't wait more and let me tell you this carbon is exactly chiral carbon yes this is Skyrim yes this is chiral carbon chiral carbon gets this is chiral carbon

now see how everyone see to it everyone see to it this is the senior most see this is carbon to carbon directly attached atom directly attached atom is iodine iodine at this iodine is not directly attached to this iodine is not directly attached because this carbon is attached with carbon and then iodine so we have to consider carbon and then iodine this is thyroid this is carbon this is also carbon these two carbons are not same because the first atom is not able to decide this carbon saying hey I am being carbon this is also

saying hey I am being carbon but your senior most is iodine and its senior most is bromine so we have to consider these now this is simply bromine and this is not simply bromine we have to consider along with bromine the Chiron is also there so we will consider it to be CBR this is CBR this is just BR this is just iodine and this is CI so this this is CI this is CBR this is just I this is BR are they different or save a kits everyone I will come to you I will

come to your house and I will just beat you if you're not able to understand I definitely I will come over there definitely I will come over there just try to understand just try to focus hey kids everyone do let me know that are you able to understand it everyone do let me know are you able to understand it you got it or not so this compound is only one Caron carbon only one Coral carbon only one chiral carbon means only one chiral carbon only one Coral carbon means what only one Coral carbon is indicating

that this compound is optically active this compound is optically active optically active no kids let me check well-known example from your biology only definitely I will give you selection kits and no teaching here for views I'm not teaching here for publicity I am teaching for your rank just give me your time and my team and myself HSP Baba will give you rankets there is nothing oh my God Sangita is saying like that okay no see well-known example well-known example that is lactic acid from your bio I am taking lactic acid lactic acid you know very

well lactic acid so you should know the formula of lactic acid if you don't know then your teacher is going to give you zero marks ch3 ch o h c o o h this is your lactic acid kits now wow case Mitra case Mitra fantastic I am really happy that you kids really studying otherwise this is not easy job this chapter is not that easy it's tough if you're sincerely with your perseverance but hard work you are really going through it then only you are able to understand and that is going to give you full

marks no secrets this is doing lactic acid and if I draw lactic acid see this is the condensed formula I would I would like to say this is being the condensed formula condensed this has been condensed formula this has been your condensed formula now let me write down properly this lactic acid then we will get it like this ch3 ch o h c o o h nuggets do let me know is this compound lactic acid is having chiral carbon yeah definitely the sari ramakanti definitely sure now do let me know is this compound if I

focus over here this carbon is chiral is this carbon chiral quick response I want in the chat section quick response yes this has been cut I'll just see to it this is carbon this is also carbon but this carbon is attached with hydrogen so this is CH we will count it c h but this is oxygen then we will say Co and this is just o and this is H just see just focus over here they are different this is ch this is just h this is just o and this is c o all they

are being different so this compound is chiral so lactic acid is optically active optically active optically active you got it everyone got it this is optically active compound now kids let me tell you CIP rule number CIP rule number three the CIP rule number three is not easy let me tell you let me explain what is the name of this batch Trisha this is Avenge this is your conquer badge concur neat unacademy conquer batch conquer itself means yes the success okay now see everyone CIP rule number three CIP rule number three CIP rule number three

just focus this is really tough rule we have to focus over here because this is going to help you in your GI also it holds a whole lot of weight again now see everyone CIP rule number three in case of in case of multiple Bonds in case of multiple bonds we have to draw we have to draw we have to draw hypothetical structures hypo hypothetical structures now kids once if you see this hypothetical structure you must be thinking you know brain that we can draw anything we have got the freedom to draw anything no kids

you haven't got freedom so hypothetical structures for comparing seniority for comparing seniority nubgets I will tell you how to draw hypothetical structures are you ready is everyone ready kids how to draw hypothetical structures I will let you know are you ready with full Josh not see everyone say to it if I give you one compound like this or examiner is going to give you one compound like this and he has written c h o and c o o h o let me take another example Santa for example ch nh2 [Music] nh2 and c n and

iodine and hydrogen he has given this compound now he's asking this compound is having chiral carbon is this compound having carbon carbon so it's very easy yes it's this compound is having chiral carbon C if I give number one then definitely this is going to get number one and this is going to get number four number one number four this is more senior this is your senior most right and this is your Junior most Junior most right kids now out of CN and this one which one is senior that is really a great product challenge

now let's compare these two compounds because the starting atom is carbon this is carbon this is also carbon both of them are being carbon so let's compare their seniority order how to compare it so just for comparison let me write it down this I've drawn it like this then let me bifurcate and first of all let me write down as they are given this compound is given like this c n can you write CN in the expanded form then I will write it like this C triple bond n c n is it okay C and

I will write like this now this C and N in between C and N there is one Sigma and rest of 2 R pi in between carbon and nitrogen one is Sigma and 1 2 R Pi anyone can be treated as Sigma and Pi now how to write down the hypothetical structure see everyone how to draw hypothetical structure hypothetical structure say Sigma bonds I will write down like this only these are the sigma ones I have written like this is it okay Sigma bonds I have written as it is in the same form now carbons

how many Pi bonds I have broken two Pi bonds I have broken so the two Pi ones I have broken will be like this two Pi bonds and nitrogens two Pi Bond have broken they will be like this is this much okay it's this much okay yes now everyone do let me know this carbon was bonded this carbon was bonded to which atom through Pi bond this carbon was bonded to nitrogen through Pi Bond so by my choice I have to write down here nitrogen here nitrogen why have written nitrogen because I have broken its

Bond I have broken its friendship with nitrogen so nitrogen atom I have to write down over here and this nitrogen was attached to carbon I have to write down over here carbon so this is the hypothetical structure this is the hypothetical structure now I am supposed to compare this with this and if I say this carbon was like this H nh2 and H2 now if I'm going to write I will write c h n and n now these two carbons are same so they are not able to decide who is senior because both the carbons

are same this carbon is saying I am attached with how many nitrogen one two three nitrogens this carbon is attached with three nitrogens can you see this carbon is saying I am looking like that I am attached with one nitrogen I'm looking like looking like looking like attached with only one nitrogen only one nitrogen right and it's attached with two nitrogens so it is looking senior but if you draw its hypothetical structure it is attached with three nitrogen atoms and this is attached only with two nitrogen atoms so who is going to be senior kids

who is going to be senior definitely out of these two this is decided to be senior this is senior so one two this will get number two this will get number two and this will get number three agreed or not but simply saying this was attached with two nitrogens and it was looking to be attached only one with one nitrogen but when we have drawn its hypothetical structure it is found to be carbon attached with three nitrogens carbon attached with three nitrogens with three nitrogen atoms it's everyone is able to understand if yes show me

the thumbs up if you're not able to decide if you are not able to understand it show me the thumbs down I will explain once again and if you are able to understand it please show me the thumbs up kids because this is the only way by which I can understand that yes each and everything is going to your brain gets how much hard effort I'm putting you can understand I'm telling you the each and everything you are not going to get these things anywhere whether you study offline you pay 2 lakh rupees three lakh

rupees you go to different city where the food is not good hostels are not good and the quality of teachers even not good so you are getting the best quality over here gets everyone very good very good okay let me tell you once again let me take one more example don't worry let me take another example let me take another example see everyone see to it let me take another example if I take if I take this atom uh c h c h two o h and c h o and hydrogen and if I say

this is bromine so definitely I would like to say this is senior most this is at the last and out of these two who is going to be senior so let me draw it let me draw it first of all because this is the single Bond only this is the single by I'm comparing these two because this is carbon this is carbon so there is tie in between carbon so this Cho let me draw this Cho in a proper way how should I write Cho choc this Chu was looking like this this Cho was looking

like this but if I write it properly The Cho is like this c h double bond o but it's hypothetical structure once it is coming that write down hypothetical structure how should I write hypothetical structure gets those who are able to understand try to find it out how to write I am going to write just you can say you are thinking it comic Sami the vermic good evening good evening yeah I would like to send not only five months you can crack neat exam in three months only three months but dedication is required perseverance is

required regularity is required patience is required now see if I say I'm going to write down its hypothetical structure this carbon is attached with one Sigma one Pi one can you see and this is Sigma so Sigma should be written as such Sigma Bond should be written as such no problem with the sigma Bond now see from where I have broken Pi Bond that Pi Bond was attached with carbon and oxygen and between carbon and oxygen so I have broken the pi one now who is who is crying who is crying carbon is crying oh

my Pi bond has been broken by HSP Baba oxygen is also crying hey my Pi bond is broken by HSP Baba so both of them are crying now I asked carbon hey carbon who has broke a newborn Carmen saying don't ask me who has broken my Pi bond with was attached with with whom this Pi Bond was attached with whom Pi Bond was attack carbon and sing by pi Bond was attached with oxygen oxygen oh take it now I asked oxygen with whom your Pi Bond was attached it was attached with carbon oh you keep

it you keep it now kids just see to it this carbon is just attached with one oxygen only one oxygen only one oxygen now this carbon is thinking like it is attached with one oxygen once you have drawn the hypothetical structure it was found to be attached with two oxine atoms so now once you are able to understand no need to write you can do it in the air once it's clear what's fundamentals are clear you can do it in here that this carbon is attached with two oxygens so number one number four number two

number three number four why I am telling you all these things not only for chiral carbon later on I am going to tell you RS system for RS system these will play really very very important role these are going to play really very very important role now you got it so this carbon is chiral this is chiral carbon and this compound is optically active chiral carbon and compound is optically active now kids just to find out whether the carbon is chiral or not no need of CIP just see with the i o of HSP let

me tell you just see with the eye of HSP if I write down this compound see everyone if I write down this compound carbon ch2 ch2 ch2 I carbon ch2 ch2 pH to ch3 now in the examination if this question has been asked will you apply CIP rule it's no need of CIP rule C this is different this is different these two are different now this has been carbon this is also carbon this is carbon this is also carbon this is carbon this is also being carbon but this is iodine so this is the winner

this is the winner so it's winner c one two three four this carbon is chiral only one current only one Caron compound is optically active compound is optically active gets so just C up to the last just try to see Abdul up to the last if no difference is there then the compound cannot be Carol C yeah RS system I will come I will come to that don't worry I will come to that don't worry I will come to that point now see kids if I write down one carbon like this if I write sarvin

ch2 ch2 ch2 phrase carbon ch2 ch2 ch2 ch3 br iodine just to let me know is this carbon Chiron is this carbon chiral kids is this carbon Caron no it's not chiral C CS2 CS2 CS2 CS3 CS2 CS2 CS2 CS3 one carbon two carbon three carbon four carbon one carbon two carbon three carbon four carbon they are exactly same these two are exactly same so these two are same so this carbon is not chiral not chiral so which case it is you can say this is like this ch2 cl2 or ch2 br2 or c x

two y two in the coordination chemistry we will study C A2 B2 all they are being same and they can't be optically active can never be optically active can't be optically active everyone able to understand can't be optically active it's everyone is able to understand or not now so question will come find out how many chiral carbons are there but before that let me tell you CIP rule number CIP rule number four and CIP rule number five two more CIP rules are there they are simple one let me tell you those yeah optically inactive so

let me tell you CIP rule number four and CIP rule number five CIP rule number four and CIP rule number five because they are easy one is equal so let me tell you pip Rule Number Four in case of Isotopes in case of isotopes the one with maximum Mass as senior most as senior most is for example if I say this is compound this is attached with h d ch3 and ch314 isotope of carbon with mass 14 is this carbon Chiron so gets those who don't know this rule they will say no but just see

this is protium this is deuterium they are treated at different atoms according to CIP rule so who is going to get number one definitely this carbon is 14 nothing is written so carbon 12 this is going to first number this is going to Second this is going to get third and this is going to get 4 so this carbon is chiral carbon everyone able to understand so this carbon is going to be chiral carbon everyone is able to understand now CIP roll number CIP rule number fine CIP rule number five so CIP rule number five

says in case of Bond pair and lone pair Bond pair senior Bond pair will be senior Bond pair is senior Bon Paris senior let me give you example example of it if I write C double bond C double bond uh C if I write negative charge lone pair and here I can write c6h5 here ch3 and here let us write down bromine so see this is the case of GI this is the case of GI so who is out of these two definitely this is senior over here and in these two this is Bond Bond

and this is lone pair or negative charge lone pair or negative charge so this is Junior and that is senior this is being Junior because lone pair or negative charge let me give you one more example don't worry let me give you one more example see the well-known example of it is nitrogen and this is the lone pair you can see lone pair this is hydrogen this is c6h5 and this is doing ch3 so see who is going to get number one this is going to get number one number two number three and this is

being lone pair number four so this nitrogen is chiral in this case carbon is not chiral nitrogen is chiral nitrogen is chiral so this compound is definitely having four different atoms so this lone pair is also considered as one group Mr Panda thank you thank you for understanding thank you thank you now see kids all the rules I've told you now just you are supposed to find out find out the number of chiral carbons in the following question is find out number of chiral carbons first example is first example is br H H how many

chiral carbons are there kids how many carbon carbons so the answer is this compound is having one chiral carbon why this is chiral carbon and this is also chiral carbon two chiral carbon so reason is this carbon is attached with bromine atom hydrogen atom this is ch2 but this is chcl same here so this is having two chiral carbons agreed or not two parallel carbons so this compound is having two parallel carbons agreed everyone is everyone agreed no C if I write down this compound ch3 c h c l c h o h C double

bond o o h how many carbon carbons are there in this compound how many carbon carbons are there in this compound gets two let me know everyone so this compound is also having two chiral carbons this can't be carried because it is attached with three hydrogen atoms this is chiral this is chiral and this is chiral that cannot be carried because it is attached with multiple Bond a carbon attached with multiple bonds can never be chiral because these are same right thank you killer science thank you thank you everyone so everyone is able to understand

how many carbon carbons are there the compound is having how many carbon carbons so once the chiral carbons are same or different doesn't matter but if compound is not having any plane of symmetry Center of symmetry then that compound is going to be optically active everyone do let me know is the screen clearly visible to all of you one girl is writing Poonam rathi that's a clear so everyone just to let me know can you see clearly yeah that's really fantastic now see kids let me tell you the most important thing I am going towards

most important thing how to find out total number of optically active thanks or not why I have told you this thing let me tell you the experimental phenomena see the experiment what scientists did they have done one experiment experiment experimentally experimentally how they perform the experiment in earlier days what was happening when somebody was getting any compound they were doing investigate investigation on that compound with the help of one instrument that instrument's name is spectrophotometer everyone says spectrophore to me too everyone say along with me spectrophotometer spectral water meter photo meter it's another name is

polarimito polarimito polari me too so actually just to find out whether the compound is optically active or optically inactive there is one instrument the name is spectrophotometer this is a question of the examination they will ask you how to measure whether the compound is optically active or inactive this is the instrument how this instrument Works see everyone how this instrument is going to work so we know that our light our light is our light is sunlight or other lights we can say they are what type of lights multi-directional lights multi-directional light skids light that is

sunlight or other lights they are being multi-directional multi-directional lights and multi-directional lights is of no use multi-directional lights now this light has to be passed through the prison we have to pass the slide through prism presume you know Nicole prison Nicole prison Nicole prison when this light multi-directional light is going to pass through this Nicole prison this light will become unidirectional kids this light is going to become unidirectional unidirectional this light will become what unidirectional unidirectional so this light will become unidirectional unidirectional this is also known as plain polarized light unidirectional you can say or

you can say plain polarized light plain polarized light plain polarized light you can see now this light plain polarized light is allowed to move through the tube this light is allowed to move through the tube this light is allowed to move through this tube and this tube is containing organic solution this tube contains organic solution the organic solution which we have to find out whether that organic solution is optically active or optically inactive that organic solution is filled in this tube everyone getting my point this organic solution is filled in this tube which we are

going to find out whether this compound is optically active or inactive if this organic solution is optically active this compound will rotate the plane polarized light let us suppose I am being plain polarized light and being plain polarized light and I am allowed to move through this organic solution see just like plain polarized light and I am going like this if this organic solution is found to be optically active it will rotate the light if it is rotating the plane polarized light in the clockwise Direction then everyone say will say this organic solution is extra

rotatory and if this ordinary solution is rotating the light in the anti-clockwise direction everyone will say that this organic solution is labor rotatory now see everyone it all depends on the organic solution okay this light which was moving in the this direction it was going like this plane polarized light if the compound organic compound is rotating that light in which direction if it is rotating this light in the clockwise Direction in this direction clockwise Direction so everyone will say that this organic solution is text to Rotator because it is rotated the light in clockwise Direction

so everyone will say this organic solution is what text row rotate trade text row row day three it is taking too much time to write Dexter rotate so so they generally call it small D small D or they can say plus sign plus sign all means same either Dexter rotatory small D or plus sign capital D don't write capital D capital D is something else we cannot write down capital D now if this compound is rotating the light in anti-clockwise direction anti-clockwise direction then everyone will say that this compound if it is rotating the light

in anti-clockwise Direction then everyone will say that is labor rotatory level rotatory or small l or negative sign either of three things we can say so just to tell whether the compound is optically active or optically inactive for that we should need spectrophotometer that is known as polarimeter without a spectrophotometer or polarimeter no one can say whether the compound is small D or small l so small D and small l no one can say by seeing the compound whether it is text to rotatory or lever rotative because it is an experimental concept and a small

d and a small L has nothing to do with capital D and capital L remember that what I am telling you first point I am going to tell you what's the first point gets small D and small L has nothing to do with capital D and capital L what I'm going to tell you gets do let me know do let me know so small d and L small D and L small D and small l is an experimental concept experimental concept no one can say whether the compound is small D and small L now small

D and small l has nothing to do with nothing to do with capital D and capital l capital D and capital l y because capital D and capital L are being relative configuration relative configuration by simply seeing the compound we can find out what is capital D and capital L but small DN is small as they are being experimentally determined experimentally determined experimentally determined or you can say these are theoretically determined theoretically critically determined critically determined it's Illinois are you able to understand wow that's really awesome Jyoti Ajay gaming now kids till now is everyone

comfortable because I'm telling you those things which you are not going to get anywhere I don't know that yes very tough to get all these things on the YT Channel you're not going to get all these things so kids do let me know are you enjoying it are you getting something from here no secrets so scientists they have developed certain fundamental things to find out what type of configuration what type of compounds they are having so either go I will move towards these configurations relative configurations number of things so everyone is ready for all these

things I was getting a lot of Knowledge from uhsb Sir wow that's really fantastic confidence no see stop configurations types of configurations so there are four types of configurations which we are going to deal for chiral carbon atoms four types and these all four types are very very important see everyone four types of configurations types of configurations of configurations for optically active compounds see everyone first one is R and F system R and S configuration this is the absolute configuration absolute this is really very very important absolute configuration second one is second one is capital

D and capital L configuration this is being relative configuration relative third one is prio and I write Trio configuration Trio and right through in 2016 question was based on this Trio and array Trio configuration and fourth one is small D and small L this is experimentally determined now number of questions are based on R and S configuration as the sequence is indicated the questions difficulty level will also be based on this that RNs system is really very very important so let's try to understand what is r and s configuration so is everyone ready for RNs

configuration so let's we are going to deal with r and s configuration R and s configuration R means R means rectus s means Sinister but don't go for their spellings R means Raptors not Cactus reactors and s means Sinister it's not Minister it is sinister sinister or you can say clockwise and this is anti-clockwise let's understand RNs configuration so we are going to deal with RNs configuration in two types of compounds the compound number one compound number one is being Fisher projection formula Venture projection formula and second is being flying version Dash formula applying wedge

and dash formula match and dash formula right fissure and bad and dash formula so first of all we are going to deal with r and s configuration in yes pressure projection formula everyone ready is everyone ready R and S qualification in Fisher projection formulas everyone ready kids do let me know r and s n facial projection formula now see so let me tell you some rules I will write down rules later on first let me explain those rules okay first let me explain those rules then only I am going to write down those rules so

draw this plus sign draw this plus sign can you see this plus sign and suppose if I have written iodine bromine let me write down iodine bromine chlorine let me take the easiest example first this is the easiest most easy kill question and this is your chiral carbon at the center at the center this is being chiral carbon this is Fisher projection now this special projection is having two types of lines what these two types of lines are indicating let me tell you first of all this compound is actually like this and these lines this

chlorine is like this this chlorine is coming like this see everyone this chlorine should be like this this chlorine should be like this you must have seen sometimes the compounds are written like this and you are afraid of what are these compounds what are these compounds see sometimes the compounds are written like this they are written like this you must have seen sometimes it's not a Goods figure let me draw it once again just wait and bromine and iodine it is chlorine sorry it's iodine iodine and bromine and hydrogen like this bromine and hydrogen like

this here bromine sorry here bromine have you seen compounds written like this have you seen the compounds like this so This horizontal line says this horizontal line says what it's do let me know horizontal line says whatever the atoms are written on horizontal line horizontal line says coming towards Observer side this indicates coming towards Observer side towards of suicide this is form writer in in foreign writer books you will see not in Indian writer Indian writer books they used to write like this and who is going to make paper definitely Indian writer is going to

make paper so you will get like this but you have to think like this so horizontal line says coming towards of zero and vertic vertical line says vertical line says going away from work so we're going are we from Observer going away from Observer are you getting my point gets do let me know first of all first of all let me let me show you don't worry let me show you let me show you wait if I show you if I show you these four atoms let me show you four atoms just say to it

everyone see to it can you see the four atoms everyone can you see the four atoms yes now try to understand in this one valency is coming towards your side one is going away from you right this black one is going away from you this green one is coming towards your side and this blue and green they are in the plane of board if I put it in this boat the screen is coming towards Observer side this blue and green and this blue and this is also green let me change the pen this is brown

let us suppose let me take this was the compound oh this is the compound let us suppose this is the compound now four different atoms and groups are there kids four different atoms and groups are there can you see everyone can you see now just see this Brown is coming towards Observer side this grain is going away from Observer and these two black and blue are in the plane of paper can you see now the same compound if I show you like this C the same compound this was the compound if I show you like

this C just C to it not two valencies same compound two valances are coming towards Observer side can you see the same compound two valencies are coming towards Observer side and two are going away from Observer at Metroid per Factory this is one V can you see the One V 109 degree see the screen is coming towards Observer side okay this Brown is going away from Observer can you see now if I show you the same compound like this now see two valencies are coming same compound two valencies are coming towards Observer side and two

are going away from observed but if I make this 3D into 2D in the copy I will say this coming towards Observer side is horizontal line and the two valances which are which were going away from you are being the vertical line now you can see the plus sign the 3D figure Indian writers they are trying to show in 2D actually it was 3d figure but they are trying to show like 2D everyone is able to understand I hope yes I hope that everyone is able to understand kids do let me know that everyone is

able to understand now the figure is given like this you have to consider it like this now how to find out RS system just say so the compound was given like this iodine bromine chlorine hydrogen rule number one says rule number one says whatever the atom directly attached to chiral carbon whatever the atom directly attached to chiral carbon as sign number one two three according to CIP rule so what should I say according to CIP rule this will get number one this will get number two this will get number three and this will get number

four right just try to understand just try to understand now the one who has got number four that is the least priority group so this is going to be list priority group kids least LPG LPG stands for least priority group everyone try to understand so we are going to find out RS system for RS system what is the rule number one kids do let me know what we have done rule number one everyone do let me know rule number one what is the rule number one rule number one rule number one rule number one rule

number one give number one two three on the basis of priority order okay number one two three four on the basis of CIP rule on the basis of what on the basis of CIP rule now rule number two rule number two says rule number two says draw an arrow draw and arrow moving from one to two moving from it's very easy just try to understand moving from one to two so I'm going to make an arrow moving from one to two just see I have drawn an arrow moving from one to two can you see

it is moving clockwise or anti-clockwise dude let me know so definitely it right now it is going clockwise it is going clockwise everyone can you see it is moving clockwise now rule number three rule number three rule number three says if rule number three if LPG means least priority group is on vertical line is on vertical line vertical line is on vertical line if LPG is on vertical line can you see this is being vertical line that for clockwise Arrow clockwise zero this is our configuration and anti-clockwise arrow this is going to be S configuration

s configuration so do let me know this compound in this compound this LPG is on horizontal line or vertical line definitely this is on vertical line so this compounds configuration is what this compounds configuration is r or S this is very simple and my school time teacher was rotating the copy and teacher was getting rotated by himself and number of things were there but it's very easy our configuration this is declared to be having our configuration so at this compounds configuration is R configuration now the rule number four says it's easy rule number four says

if LPG is on horizontal line then clockwise will be S and anti-clockwise will be R it by chance rule number four see rule number four says rule number four says if least priority group is known horizontal line is on horizontal line then gets what will we will say then clockwise arrow for clock by zero we will say it is s configuration and anti-clock by zero it will be R configuration our configuration now the problem is once the time is getting passed later on you won't be able to remember it where was the LPG what we

have to decide so again and again you have to revise so we have not to do things like that that we are going to revise again and again we should need some parameters some trick like that no need of further revision so let's see let me give you one trick HSP trick see everyone HSP Baba's trick HSP panda HSP Baba's trick what I said what I said LPG I am talking about LPG everything is moving around LPG if LPG was on vertical line when LPG was on vertical line LPG was on vertical line and arrow

was moving yes Arrow was moving clockwise what we said LPG on vertical line Arrow was moving clockwise completed what we said it is R configuration we said like this and LPG was on vertical line and arrow was moving anti-clockwise what we said as configuration we said like this we set like this or not do let me know in the chat section we were talking like this or not when LPG was on vertical line Arrow was moving clockwise we said it's r s and if LPG if LPG is on horizontal line and arrow was moving clockwise

we said it is s configuration and LPG was on horizontal line and arrow was moving anti-clockwise we set R configuration right is it right or wrong kids do let me know we were talking like this only or something wrong when LPG was on vertical line Arrow was moving clockwise we said our configuration vertical line anti-clockwise S configuration horizontal line clockwise s configuration now so see what's my name my name is my name is Hari Indra a r h a r this is my name h a r you can remember h a r now VCR very

clear very clear very clear are our bones very clear are R means you can you can write anything for R very clear r r means make make code for this make trick for it everyone make your trick very clear r r means anything you can say very clear very clear very clear RR means very clear and Excellence very clear very clear right very clear anything anything you can say very clear Road very good nowadays road is not getting clear do you see you see him on the Himalayas badrinath roads are not clear very clear Road

very clear Road wow that's fantastic very clear route you can say very clear route very clear wrote very awesome concept very awesome very awesome oh my God very clear road so very awesome very awesome system very clear road so very awesome very awesome s s very awesome what very awesome subject wow very awesome subject very awesome yeah subject very clear Road very awesome subject HCS at CS CS you can make anything at CS at CS now you got it everyone got it are you able to understand now see once you got it let me know

very awesome season very clear road so very awesome season subject or season wow that's fantastic very clear Road very awesome subject or season now you can make your fundamentals your tricks now you're perfect you are perfect now see I'm going to give you question try to do it once if it is clear to all of you one compound first compound let me say let me say here is uh uh iodine here is bromine here is chlorine here is ch3 so number one number one should be given to definitely number one should be given to iodine

number two to bromine number three to chlorine and number four to ch3 and this is least priority group am I right everyone try to find out what is the configuration you are going to give now I have to draw an arrow moving from one to two this arrow is going clockwise or anti-clockwise anti-clockwise and take clockwise so least priority group LPG is on vertical line arrow is going anti-clockwise very awesome very awesome very awesome what very awesome s configuration V A as fantastic your answer is absolutely correct so answer is as configuration s is as

answer is s configuration everyone is able to understand is everyone able to understand this question not see second question I am going to give just try to give me the answer for this question so see if I write o h if I write ch2oh if I write ch3 and if I write hydrogen to whom should I give number one to whom should I give number one kids do let me know to whom should I give number one over here number one should be given to o o it's only o this is C and this is

C it's O number two number three number four so LPG but first of all I have to draw an arrow one to two arrow is going clockwise so LPG LPG is on vertical line arrow is going clockwise we see very clear very clear Roots so it is having R configuration R configuration everyone are you able to understand or not now I'm going you to give you one tough question see everyone say to it I am going to give you one tough question if the question is like this I let me write down over here I

br idgen chlorine number one should be given to number one should be given to iodine number two bromine number three chlorine number four this now it's there is one problem one to two we cannot go directly either we have to cross hydrogen or we have to cross chlorine kids try to understand number one is over here number two is over there so if we are going from number one to number two this arrow is going clockwise and we are going from number one to number two this arrow is going anti-clockwise you can see there is

problem so this is going anti-clockwise if we are going clockwise in the way there is chlorine and we are going anti-clockwise during the way on the way there is being hydrogen so which way is correct that is the toughest question from which side we should go so remember that while moving from one to two while moving from one to two we cannot cross highest priority group the third highest priority group we can cross LPG if this type of situation is there do remember while moving from one to two while moving from 1 to 2 1

to 2 we cannot cross we can't cross we can't cross third highest priority group so we have to cross so we have to cross LPG list priority group we can cross so this is the right approach that is wrong that one is wrong this is right so what we are going to do LPG is on vertical line LPG is on vertical line arrow is going anti-clockwise very awesome session s configuration configuration is s Everyone able to understand is everyone able to understand kids is everyone now if you are able to understand I am going to

teach you two things try to understand try to understand first of all I will give you question and then I will explain it everyone try to understand the most important question for number of examinations is being asked like this find out the relation find out the relation in between say this is a and this is B a is a is like this B is like this everyone try your best to answer it I br c l hydrogen and here is I PR hydrogen so first option is enantiomers second option is Dice tumors third option is

homomers homomers also means identical fourth option is none of these then I will let you know each and everything about it related to it but first of all try to answer it let me check it out how much you know by your own knowledge yes is giving answer one killer science is also going for one now kids let's find out the answer of this question this question is looking simple but it may be simple or it may be tough it depends which logic you have applied have you applied any logic or not seen this compound

is having just one chiral carbon and this is having one chiral carbon so see try to find out the RS configuration if I say Let me give number one number two number one number two number three number four LPG right now let me draw an arrow arrow is moving from one to two in clockwise Direction an LPG is on vertical line so vertical line clockwise Arrow what should I write v c r this compounds configuration is declared to be R configuration agreed or not everyone agreed or not write down in the chat section our configuration

somebody is writing dice tumor somebody is writing diastomer C now same thing I am going to do away one two and this is 3 and this is 4 this is LPG Now Arrow is moving anti-clockwise anti-clockwise but LPG is on horizontal line so LPG is on horizontal line and arrow is moving anti-clockwise what should I write R configuration so this was our configuration that is also our configuration am I right or not this is attached LPG is attached on a horizontal line LPG is on horizontal line and arrow is going anti-clockwise R configuration so its

configuration is also R configuration am I right or not configuration wise am I right or not kids do let me know everyone do let me know the configurations whatever the configurations I have written are they correct or incorrect they are correct so this is our configuration are you able to understand anything this is R this is R I don't know whether they are dextro whether they are Libo but they are same they are identical they are identical so answer is neither enantiomer nor dice tumor they are declared to be homomers and they are identical everyone

got failed or not is everyone got failed or not gets do let me know everyone got failed or not as everyone got failed or not so those who got the wrong answer show me the thumbs down if your answer is Right thumbs up so now see let me give you one trick let me give you one fundamental trick not the trick better to say fundamental trick fundamental trick if if any compound is having only one chiral carbon only one caral carbon only one parallel carbon depending compound is having only one chiral carbon then first isomer

second isomer relation if the first isomers configuration is r and second is also r or the first is s and second is also as the first is R second is s the first is as second is R what I am going to write kids try to understand everyone try to understand what I am going to write just apply your brain what should I write you have just think by yourself what I am going to write what I am going to write r r r and r are identical so definitely I will write R and R

being identical so identical and identical are also known as homomers SS being identical r s being enantiomers enhancumers and s2r is also being enant Schumer now kids you must start thinking where the dice tumor has gone remember that mark my words if any compound is having only one chiral carbon then dice tumor will never exist they will never show the relation of diastereomerism remember my point remember my words if see just see to it everyone are our identical SS identical R to S enantiomer s2r is enant Schumer if any compound is having just one chiral

carbon mark my words everyone what I'm saying a a compound if a compound is having only one chiral carbon only one viral carbon then it will never have tired stereo March with respect to chiral carbon now you must be thinking sir why why so for that we should know the definition of diaste tumor let me explain it first of all let me tell you the definition of diastoma what are dice tumors what are diastomers how will you Define diet tumor is there anyone who is going to tell me what is the definition of diastoma so

dice tumors Dias tumors are those stereoisomers die stereomers are those stereoisomers which are not mirror images of each other which are not mirror images of each other or we can Define dice tumors in another way see in what way we can Define diastromers we can also say those stereoisomers which are not enantiomers those stereoisomers which are not enantiomers which are not what which are not enantiomers are diastomers are nice tumors now kids let me Define in a simple way let's keep it very simple see to it everyone see to it if I say see chlorine

chlorine bromine iodine is Mr X is Mr X this is one man this man's name is being Mr X this is the name c f c l b r i Mr X name now this Mr X is having 1000 you can say 1000 uh Arya daughter 's name is 1000 Alia it's just artificial 1000 Alia and one thousand Italian both are the daughters of Mr X now could you please let me know what is the relation in between Ali and Thalia these two are the daughters these two are the daughters of Mr X what is

the relation in between Ali and Talia do let me know what is the relationship in between Ali and Thalia everyone in the chat section definitely they are being sisters they are being sisters so if any compound is having only one chiral carbon this is having just one chiral carbon one chiral carbon I will let you know that it can have just two isomers one is r and one is s this is R then this is as if that is s this should be R so they are sisters now let me tell you one thing one

day what Mr X has done Mr X Switched Off the Lights Mr X Switched Off the Lights and said Alia and Thalia thousand Aliyah and thousand Talia randomly just hold your hands Alia and Talia without no light was a thousand alien thousand Talia just randomly by having one cloth over the eyes and he said just hold hands Ali and Talia now once the light is there once the light is switched on then this Alia may be possibility that Alia is holding the hand of Alia Alia is holding the hand of Alia it is possible it

is also possible that Talia is holding the hand off Talia Talia is holding the hand of Thalia and another possibility is that Alia could be holding the hand of Alia could be holding the hand of what Tanya Ali and Talia right these are the only possibilities kids do let me know is there any other possibility no other possibility is there once Alia is holding the hand of Alia once the light has switched on they will say oh we are identical what relationship we are having we are identical or we are Homo mods homo much once

the light is switched on Alia and Talia what I said Ali and Talia is like RS if this is our Alia this is our this is also our identical if this is as this is as identical and if this is our this is as what they will say oh we are now let me tell you what is the definition of financiomers now one thing is clear to all of you that if only two types of things are there then only one relationship can exist not more than one relationship either they will be identical identical is

not the relationship or the relationship is there that only one type of relationship no second type of relationship yes if Alia is there Talia is there brother changu is there then definitely Ali Alia identical Talia Talia identical Ali Italian sister Alia changu brother two types of relations so for two types of relations at least two chiral carbons should be present so for a compound to be diastoomerism so compound to show diverse tumorism at least two current carbon should be there gets are you able to understand what I'm talking about now let me tell you what

are enanti summers let me explain enantiomers gets it's not easy at it's not easy to teach also it's not easy to teach also the subject this Optical isomerism yes now see let me tell you about and I assumers what are anal schumers tickets let me tell you about enantiomers let me take example of lactic acid lactic acid is well known as it lactic acid so lactic acid ch3 ch o h and let me draw because we know RS system RS system though we know very well so let me draw this is lactic acid c h

o h t o o h ch3 so this is lactic acid and if you see this lactic acid in Mirror let me Place mirror let me Place one mirror this is mirror and if you see this lactic acid in Mirror how it will look like it's this lactic acid will look like this o h ch3 c o o h and H so these two are mirror images once if I am going to explain these mirror images first let me ask the thing which you are having with yourself because this is so chemical compound you are

having your right hand you see in right hand there is no plane of symmetry if you divide this hand from any side you won't be able to divide in two equal parts so if you see this right hand in the mirror you see this right hand in the mirror you will see your left hand just try to see if you are having mirror just go smoothly not in hurry otherwise leg should get broken up take care of legs go slowly see your right hand in the mirror you will get left hand just see go and

watch Sunny Duhan welcome you see if you try to see right hand in the mirror you will get left hand you see let me show you mirror over here only see you will see it like this just see to it this is going to see in the mirror it will look like this just see this is the mirror just say this is the mirror in between this this is the mirror if this hand is going to see in the mirror it will see like this I'm good Sunny Duhan I'm good but not just to let

me know this right hand and left hand are identical or different everyone do let me know you must be having your right hand you must be having your left hand everyone you let me know is your right hand and left hand being identical or they are being different Priyanka is saying different killer Sciences saying identical kids just see your right hand and just see your left hand so shiv Kumar is saying obviously it's identical it's welcome welcome now everyone you have to understand okay now during Winters if you are having gloves during Winters if you

are having gloves the finger the gloves having fingers is it possible to bear that right hand gloves in the left hand or left hand gloves in the right hand is it possible need two zero to four it's do let me know if you are having right hand gloves finger one claps comfortably is it possible that with that is you can take you can put on those right-handed gloves in the left hand know that means right hand is right hand left hand is left hand when they don't know about our hands how we can understand the

science in the starting 99 maturity of this trend they set a right hand and left hand being identical no kids by chance in some months if someone's hand is taken by God and God is saying in place of right hand let me give you five left hands by chance if after 200 years just say if after 200 years if God is saying oh HSP Baba give me your right hand and I will give you five left hands so is it possible to place this left hand in place of right hand C if surgery is being

done and if doctor is going to put this left hand in place of right hand he will bring like this and it is going to bring like this he will attach to this radius and he is going to put it like this and see the right hand was having thumb on this side left hand will be having thumb on this side and if he's going to join it like this then you see the right hand was having smooth surface the left hand thumb will come to this side but the shrunk surface so right is right

left is left right hand and left hand they are mirror images of each other they are looking like identical but they are not identical at all they are two different hands right hand is right hand left hand is left hand they are looking identical but not at all not at all they are being identical so this much knowledge you should have to have if you want to get command on chemistry visualization is necessary whatever the subject you were studying you are going to study this much of command you should have to have and you you

should have to go for it gets so this is the enantiomeric image of this they are known superimposable now see what is non-super impossible once the compound is not having plane of symmetry or scent of symmetry if you put this compound over this the mirror image if you put this compound on the mirror image now see superimpose means completely it is going to cover no see the thumb is there thumb is there you rotate that this hand you rotate this hand you see rotate you won't be able to cover it up clearly so don't put

like this that's not allowed in the plane of surface you can rotate by 360 degree and it won't be able to cover it up so this is known as non-superimposable Mirror Image now see kids this compound this compound if I rotate 1 2 the light is going in which direction this is r or S this is being LPG LPG and the light is the arrow is going in the anti-clockwise direction and LPG is over here so this is having s configuration and you see the mirror image will definitely have R configuration let me write down

R I'm not going to find out the answer automatically it is going to R there see number one number two number three number four exactly it is moving clockwise and LPG is over here so this is R qualification so these are non-superimposable mirror images of each other so they are enantiomeric Pairs and Ensure medic pairs that is known superimposable mirror images known super impossible not impossible impossible mirror images of each other mirror images of each other mirror images of each other gets so these are enantiomers everyone is able to understand kids you liked it so

today always remember that right hand is say to left hand a you are my enant Schumer left hand side left hand is sent to right and a you are my enant Schumer we are not identical we are an isiomeric pair everyone you can say they are looking like identical with they are never identical they are enantiomeric pairs I will let you know water um miso compounds let me tell you but this thing you are able to understand everyone is able to understand not see thing is rationalization once we are able to understand enantiomers let's understand

decimalization also one by one we will move one by one officer juice first of all let me know how's the Josh have you got bored because it's almost three hours it is going just 20 minutes left for three hours have you got bored or you are enjoying it everyone just to let me know Veera level wow thank you everyone is enjoying it or you got bored because the label of this Optical isomerism is super super awesome now everyone if you're liking it call your good friends see HSP Baba the awesome teacher is teaching you know

where you are going to get this much of quality gets tell your friends you you don't think like that if I'm going to tell my friend that he is also going to get that much of knowledge then the competition level will increase no kids if your friend is preparing along with you you have to prepare more heart because always he will let you know that yes I am there so both of you are going to get more than 700 marks so you are ahead of rest of others so whether your friend better your enemy if

he is really hard working or she is really hard working everyone tell your friends wow quick very clear Road very awesome chemistry wow wow subject by harinder chemistry sir highly active rank me oh my God trick just wait killer science what he's writing wait wait very clear let me write down very clear route very awesome chemistry subject very awesome subject Chemistry by harendra chemistry sir by harendra chemistry sir highly active rank maker oh my God highly active rank maker see everyone take the take the what pick of this WOW wait wait wait wait wait wait

let me see let me see let me write down what killer science has written very clear route very clear wrote then very clear Road very awesome subject very awesome subject then harendra highly active rank maker highly active rank maker harinder sir Harin sir highly active rank maker one is left h c s what's that see very clear route very awesome subject are in sir highly active rank maker wow claps Taylor science clubs really now only one is wrapped one is left XCS what is that let me write down more that's really awesome trick by alert

science very clear Road very clear route very clear Road very awesome subject very awesome subject highly active rank maker Harin sir highly active rank maker and insert no only one is left at CS what's that at CS everyone try harendra chemistry sir yes one only one is left at CS this is for RS R and S configuration R and S configuration that's really awesome this is mind-blowing no one is having this trick nowhere in the whole world no one is having this type of trick now only one is left only one is left at CS

what's that H C S everyone chemistry sir yes chemistry even I forget I forget an app forgotten this chemistry sir arendra chemistries now let me take pic of it even I am not having this trick the whole trick even I am not having let me take the one pick of this I have forgotten it little bit I made in one class that's really awesome fantastic it's even I have taken the pick you can take yes the screenshot that's really awesome wow claps from my side claps to killer signs fantastic the whole class whole class efforts

are there and maximum from the killer signs that's really fantastic now see really awesome I appreciate your hard work this type of hard work is definitely going to give you the best rank in your examination no see everyone now let us suppose if I'm taking uh 60 percent dextrolactic acid dextrolactic acid and 40 percent labo lactic acid level lactic acid now what do you think it is just like if I take 60 Milli equates of acid and 40 milliculates of Base what do you think does the neutralization process will take place 60 milligrams of acid

and 40 milliculins of Base definitely wow thank you killer science that's fantastic so definitely here that dextro will neutralize the levo and cancellation of Optical rotation will take place cancellation of optical rotation this cancellation of optical rotation is known as restomization but do you think that complete cancellation will take place no partial cancellation partial cancellation of optical rotation partial completion cancellation of optical rotation will take place this cancellation of optical rotation because dextro suppose if light is moving like dextro and other compound is moving it like in the level Direction so partial cancellation will take

place this partial cancellation is known as partial rasmisation this partial cancellation is known as gets partial restomisation this is only known as that is partial rasmidation partial no this razzmatician partial cancellation of rotation is in the same compound or two different molecules are there definitely two different molecules are there because dextro is different molecule level is different molecule so the reason is Q2 external compensation external compensation what is this external compensation kits external compensation means in between two molecules in between two different molecules or Innovative enantiomers in between enantiomers this is happening taking place in

between and tumors now if anyone is asking this is case one if anyone is asking now this mixture is optically active or optically inactive do let me know this mixture is optically active or optically inactive so the answer is definitely this mixture is still optically active why this mixture is still optically active will say anyone who is going to let me know why this mixture is still optically active this make sure is still optically active why this is still optically active gets anyone is there anyone because enantiomeric axis one enantiomer is in excess amount so

this is because of enantiomeric access because of because of an isometric access and ensure medic access everyone is able to understand so it is just like it is just like if I'm I'm feeling I'm starving I'm starving starving means I'm feeling hungry and somebody has given me one truck Pizza one truck Pizza somebody has brought for me one truck full truck of pizza so if I'm going to eat is I'm going to eat the whole pizza how much starving how much hungry am I doesn't matter but the pizza will left over because the pizza is

an excess amount or suppose if I'm too much hungry and somebody is going to give me just one piece of pizza so my hungerness will remain over there because that that desires the last amount limiting region that will not be able to neutralize my hungerness still I will be feeling starving everyone able to get it it will show decks to rotation because dextro is an access dextro is an access so the mixture will be dextro rotatory so that the mixture will be dextro rotatory mixture will be dextro rotate tickets you got it dextro dextro rotating

now case two no case to see everyone this is really awesome try to understand and you have to answer it means number two if I talk about case number two everyone see to it if I take 50 percent 50 percent dextrolactic acid and 50 percent labo lactic acid everyone do let me know 50 dextrose and 50 level lactic acid mixture let us suppose this green one is dextro green one is being dextro and this yellow one is Lebo do let me know what will happen what will happen dextro will completely neutralize the level and this

time complete restimization will take place am I right or wrong complete rest magician will take place complete rasmization will take place right complete rest magician and the compound is optically inactive as a whole compound will be optically a mixture will be optically inactive mixture will be optically inactive have you got it everyone got it kids do let me know that everyone is able to understand do let me know everyone everyone is able to understand yes everyone is able to understand now everyone must be waiting for me so one miso isn't it everyone must be waiting

for miso but before telling you miso before telling you miso let me tell you if any compound is having how many chiral carbons then how to find out total number of optically active isomers how to find out total number of optically active isomers okay Now secrets before I move ahead do let me know that how much you are liking my teaching is it different something different or it is just bookish knowledge whatever I am teaching you here the things are really required for visualization is this bookish knowledge or something out of the box now say

everyone how to find out yeah we can write calculation of calculation of total number of optically active isomers stay everyone oh foreign put some cake top notes awesome to the gore so you are your sessions are thank you Shiva Kumar now everyone put some cake or thumbs up sign or write down happy birthday to Javeria Syed everyone because the stage is really special and you have to understand subtle now I never seen the third teaching like listen like you're very class after one are definitely class will be bored but I can say that just be

sir class never get bored oh really thank you thank you thanks Javeria Sayer May almighty God bless you with all happiness and prosperity along with the best Rank and successful life ahead this is my pray to almighty God now everyone calculation of total number of optically active isomers when foreign no form or representation no representation of that compound have any element of symmetry that is pause and pause now its formula is total number of optically active isomers total number of optically active isomers is equal to 2 raised to the power whole n 2 rest powerful

and Kids 2 rest per whole n what is this n could you please let me know could you please let me know what is this n definitely this n is going to be number of chiral carbons where n is equal to number of chiral carbon atoms chiral carbon atoms now see everyone everyone see to it how to do it so suppose if examiner is going to give you glucose examiner has given you glucose just find out total number of optically active isomers for glucose gets glucose if we don't know glucose just we know that C6

h12 o6 we cannot find out for this we should know the structure of glucose see everyone the structure of glucose am I right or wrong do let me know I'm trying to make it c h double Bondo C H 2 O H 1 2 3 4. c h o h c h o h c h o h c h o h kids do let me know have I drawn it properly or not you are really intelligent kids everyone do let me know everyone do let me know have I drawn this glucose properly or not properly

now see this is joined with multiple one can't be carried one kernel two kernel three kernel four Carol how many chiral carbons gets this glucose is having this is open chain structure open chain structure or simply we can say glucose this open chain structure is having n is equal to four is equal to four so total number of total number of optically active isomers will be 2 raised to the power 4 that is 2 4 8 should I write down eight or two to four to eight to sixteen what should I write down 2 4

8 or 2 into 2 into 2 into 2 that is being sixteen what should I write down 16. so I 2i is 16 everyone is able to understand now kids once they have given a particular question categorically I am telling you what question they have given secrets they have given this question really this question 50 percent of the coaching one not able to give the correct answer for this question see kids what question they have given they have given question find out total number of optically active isomers for Alpha D glucose Alpha D glucose no

kids those who those who don't know what is Alpha body glucose how they are going to find out total number of optically active isomers so what we are supposed to do gets try to understand Alpha D glucose I am going to write just to let me know am I right or wrong I'm just trying my little best and you have to support me if I'm wrong do let me know sir you have drawn it wrongly absolutely you have drawn it wrongly okay kids ch2oh now one two one two three four five h o h o

h h o h h o this is first carbon first second third fourth fifth sixth do let me know that I've drawn it properly or not is this Alpha D glucose or not yes this is Alpha D glucose now how many chiral carbons this is having do let me know one chiral two caral three caral four Carol and this is one new chiral carbon you can see this is new chiral carbon and this is known as anomeric carbon I will let you know why it is known as anomeric carbon that I will tell you later

on but yes this is also chiral carbon anomeric carbon now kids the hemiacetyl this is known as hemiacetyl Hemi acetyl pyranose glucose structure amiaceto paranose glucose structure and this is having value of n the value of n is equal to 5. so total number of optically active isomers will be equal to 2 raised to power 5 that is equal to 32 like our teeth or paristormal theats in bryophyta teridophyta wherever you must have studied 32 everyone do let me know are you able to understand it or not everyone do let me know everyone are you

able to understand it or not yes so whether it is Alpha D glucose or beta D glucose whenever it is cyclic structure whenever they are going to ask for cyclic structure do remember cyclic structure will always be having 32 so when nothing is given no problem now six kids when simply glucose has been mentioned when simply glucose is mentioned the total number of total number of optically active isomers will be 16 when Alpha D glucose or beta D glucose or pyranose ring structure of Uranus ring structure is mentioned ring structure is mentioned whatever the ring

structure is mentioned then all in these three cases the total number of optically active isomers will be 32 and for fructose if fructose is given kids fructose is given then it should be two threes are eight and a ring structure of Uranus ring structure or any pure nose ring structure is given Alpha D or beta D doesn't matter it can be alpha or beta then it should be 16. now you must be thinking sir for fructose how to do it how to do it for fructose no secrets if you know the structure of fructose this

is fructose ch2oh c h o h c h o h three carbons four carbons c h o h five carbon c h o h six carbon ch2oh now see everyone this is not Carol this is not car this is current oh this is not fructose here it should be C double bond o right it's this is not Carol this is not Carol this is Carol one two three only three carbon carbons are there kids so n is equal to 3 so total number of optically active wide Summers will be 2 raised to power 3 that

is being eight everyone got it now if I draw its ring structure how I will draw just C to it c o h c h o h C it's not c o h carbonyl group carbonyl group so c c h two o h c h two o h and the c o h one carbon second carbon third carbon fourth carbon fifth carbon six carbon one two three four five six ch2 o h and this carbon's oxygen is attached with this and c h o h c h o h t h now you see just see

to it this is first carbon second carbon third carbon fourth Garden fifth carbon six carbon and this is anomeric carbon this is one new chiral carbon and this o h and this oh are on opposite side so we'll say alpha alpha d fructose Alpha d fructose no kids you can see how many chiral carbons are there of one chiral carbon two three four so this is puranos ring structure you can see Hemi Ketel furano string structure Hemi kettle Uranus ring structure pure nose a ring a structure so here the N value is equal to 4

so 2 raised to the fourth that is being 16 everyone is able to understand gets how is the energy level gets how is the energy level if pure energy level is getting down do let me know I will take second part of Optical isomerism if your energy level is okay then do let me know everyone do let me know how is the energy level are you able to understand each and everything FPS then do let me know need break okay okay everyone is asking for break so let's do one thing right now it's 21 10

means nine ten past nine right now it is ten past nine so okay so let's meet at nine Thirty that will be better 9 30 should we meet at 9 30 everyone 9 30 everyone do let me know 9 30 will be better Okay so let's meet at 9 30. but you have to come back okay you have to come back promise it will take let me tell you I will take two sessions for this this is the first half second half means after break break I will let you know but it is not going

to get completed one more lecture I will take okay it's or I will try I will try to complete it within one or one and a half hours but if it is not getting completed then it will require one more lecture then I will let you know okay so everyone you have to come with full-on energy not to come only you are supposed to come with full energy right everyone you have to come with full energy so it's a break energy break right energy break foreign foreign this is your Concord batch everyone just see am

I on time or not I'm better to say in time right or you can say on time it doesn't matter but yes my all dear swings I think now you can study with more Focus because you must have taken something some source of energy so Keller science is there rest of other students are there yes you're on time so time is really very very important but yes to study the full-on energy ultimate suits of whatever the things that is the energy energy atps they are also required simultaneously so it's better to have break after short

time welcome welcome so without wasting even a single minute let's start once again let's back so kids I was telling you about the rationalization and I have told you that you must be waiting for meso compounds before I proceed towards meso compound let me tell you very clearly the case number one and case number two because there's too much difference in between case number one and case number two so here is case number one with the white line and here is case number two so what's the difference between case number one and case number two

let's try to understand case number one and case number two just see in case number one as I have told you in case number one as I have told you what total number of optically active total number of optically active isomers is equal to 2 raised to power n this case I have already explained then what's the need to tell you once again yes this is the point C 2 raised to power n where n can have even or odd this n can be even or odd the number of isomers will not get changed the

value of n can be even or odd doesn't matter but the condition was required for case number one the condition was no isomer no representation should have plane oximetry or Center of symmetry this was a condition required over there for the case number one then only this case was valid now if I talk about case number two case number two kids if any representation of compound if any representation of compound is having plane of symmetry or Center of symmetry the total number of optically active isomers will not be equal to 2 raised for n they

will be less than that total number of optically active isomers value will be less than this then the formula will get changed and this compound case number one there was no meso I talked for this case number of mesoisomers number of mesos for zero was Zero no meso isomers were there but this case number two the value of meso should not be zero for this case meso isomers will not be equal to zero they will have some value means in case number one there is no meso isomer but in case number two meso isomers exist

and I will let you know here if n is even then different formula if n is odd then different formula so even an odd will have different formulas so two sub cases will arise to sub cases will arise what are the two sub case sub case a and sub case b sub case a with even number of chiral carbons that's the value of n is even even number of parallel carbons and sub case b odd number of parallel carbons odd number of parallel tolerances and they will have different formula now everyone ready is asking this

formula is valid only unsymmetrical compounds yeah this formula is valid for unsymmetrical means when none of the representation then how to find out whether the compound is belonging to case number one or case number two this question must be arising in your brain then how to find out whether the compound is belonging to case number one or case number two this can be your question now see let me check C if I draw one compound like this try to understand try to understand the difference if I draw one compound like this cn3 c h br

c h uh something o h ch2 c o o h this is first compound and if I draw second compound like c o o h c h b r c h br c h three now let me draw third compound t o o h c h b r c h b r c-o-h because in the examination no one will be there to tell you that this example belongs to case number one or case number two no one will be there you have to decide by yourself now see try to understand whenever you are going to

find out whether it belongs to case number one or case number two see from your extreme right hand side and extreme left hand side on the extreme right hand side there is coh and extreme left hand side there is ch3 are they same or different are these two same or different let us say this is R1 and R2 R R1 R2 same or different they are different so this will belong to case number one this belongs to case number one that no symmetry never symmetry can exist same symmetry can not be present in this compound

same just see extreme right hand side and extreme left hand side are they same different they are being different they are being different so this also belongs to case number one it's number one now see in the last compound the right hand side is coh the left hand side is being coh now start moving from right hand side towards center right hand side towards Center will start moving and from left hand side towards Center you start moving you see the Symmetry is appearing the Symmetry is happening that means this belongs to case number two this

is case number two everyone are you able to see can you see how to find out whether the compound is under the category of case number one or the under the category of case number two is everyone able to understand do let me know in the chat section are you able to understand whether it is going to block case number one or case number two yeah yeah sure made I will I will definitely definitely now everyone is able to understand now see so let's deal with case number two so I'm going to deal with case

number two everyone see to it case number two now case number two sub case a sub case a so total number of total number of Optical isomers Optical isomers is equal to tal number of optically active isomers Plus meso isomers meso isomers not just C what is the formula for this 2 raised to power n minus 1. see total number of optically active isomers in the earlier case it was 2 raised for n but here 2 raised to power n minus 1 power minus 1 plus 2 raised to power P minus 1 now what is

this p where p is equal to where p is equal to n by 2. n by 2 What is the value of p p is equal to n by 2 this is the formula now let's apply the formula by applying formula we will try to find out the answer at manually also we are going to do it means with the help of visualization both the methods I am going to apply without formula bit Formula First let's find out one compound with formula so everyone is agreed now see just try to find out let me take

example of tartaric acid let me take example of tartric acid now the question arises how to write down tartric acid just try to find out ch3 ch o h so that was lactic acid this was lactic acid you can understand this was lactic acid can you understand lactic acid now from the lactic acid remove this ch3 now same thing repeat on the left hand side same thing gets repeated ch o h c o o h this is the way how to write down tartaric acid gets examiner can ask what is the formula of tartric acid

once this question has been asked in your previous examination was the formula of tartric acid how to write down tractic acid this is tartric acid so let me write down tartaric acid properly c o o h t h o h c h o h c o o h now in the examination no one will be there to let you know whether this belongs to case number one or case number two what I have to do just see your extreme right hand side and just see your extreme left hand side now let me know if you

see your extreme right hand side and once if you see your extreme left hand side do let me know that if you move from that side towards this side both the side you will get some symmetry over there this side and toward this side you will get some symmetry can you see that means it exactly says it belongs to case two it belongs to case to everyone now see so how many caral carbons are there if I say Cara carbon this is one chiral carbon and this is being second chiral carbon two chiral carbons are

there so an N value is equal to two everyone got it the value of n is equal to 2 now just apply total number of isomers total number of isomers is equal to total number of optically active isomers total number of optical isomers is equal to total number of optically active isomers plus meso isomers meso isomers and what was the formula gets formula was 2 raised to power n minus 1 plus 2 raised to power P minus 1 and the value of P was n by 2 minus 1 so if I apply the formula what

I am going to get 2 raised to power 3 minus 1 plus 2 raised to the power not 3 the value of n was 2 only you know the value of n was 2 2 raised to power 2 minus 1 plus 2 raised to power 2 by 2 minus 1 how much it is going to come 2 raised to the power 1 plus 2 raised to the power 0 so 2 raised to the power 1 will 2 and any power 0 is 1 so the answer is coming out to be 3. you can see very

clearly everyone now total number of optically active isomers if anyone is asking total number of optically active isomers 2 and total number of meso that is one number of meso is being one now formula just increases the speed formula is not going to tell anything it's not going to visualize it's not going to give you knowledge about it it is just telling you speedily the correct answer so if you don't know if you don't have knowledge you won't be able to apply the correct formulas so we should have in-depth knowledge so how many of you

ready to get in-depth knowledge of this no this is your tartaric acid and we are not able to understand anything about tartaric acid tartaric acid now let's see the visualization this is the formula waste this answer we have got just formula based formula based also we have obtained speedily we got the answer we are not able to understand too much yes Priyanka very good now see the same thing we are going to visualize now visualization part see to everyone see to it visualization part if I draw if I draw the compound I will draw it

like this this is being tartaric acid just situate everyone this is being tartaric acid c o o h c h o h t h o h and c o o h how many chiral carbons are there definitely one Carol and second Coral two parallel carbons are there everyone say to it no plane of symmetry is there two chiral carbons are there and no plane of symmetry there so plane of symmetry is not present so this compound will be optically active that's why this compound is optically active this form of compound is optically active just see

if this is being optically active I will let you know one more thing if this compound is optically active both the chiral carbons configuration will be same either they will be RR or they will be SS but both the chiral carbons configuration definitely is going to be same just see to it if I say this carbon so number one CIP rule number two CIP rule number four this is being LPG least priority group and this is going to be third now if I move an arrow one to two how it is moving clockwise or anti-clockwise

definitely it is going anti-clockwise so killer signs you made one trick now help me so one to two LPG is on horizontal line horizontal line anti-clockwise Arrow R so this is said to be R configuration agreed everyone agreed our configuration so definitely this will also come out to be R only C it will also come out to be r 1 2 and arrow is moving just C anti-clockwise anti-clockwise and least priority group is one horizontal line right [Music] so this is also being R configuration so RR configuration now one fantastic thing I am going to

tell you if I put one mirror over here so we will get the mirror image of it we are going to get mirror image of it so I placed mirror this is mirror let us suppose mirror now in the mirror we are going to see we'll get mirror image of it see to it to everyone what's the mirror image we are going to get we will get something like this it's mirror image o h o h c o o h c o o h so this is the mirror image of this compound and we know

that when the compound is optically active means not having plane of symmetry then its Mirror Image will be the enantiomer and already I have told you for opposite of R opposite of R it should be S opposite of R it should be S that means it is supposed to be having ss configuration but let me note write down just try to find out if it is not SS then I am a bad teacher I am not a good teacher and if it is SS then definitely whatever I taught you that's going to be get proof

definitely now see everyone so if I write here is 1 here is 2 arrow is going clockwise and LPG is on horizontal line LPG is an horizontal line arrow is going clockwise HC what should I write h c h c n so this is being s configuration right now here in this if you see if I say 1 2 arrow is going clock by zero arrow is going clockwise and LPG is on horizontal line so horizontal line arrow is going clockwise s s configuration so opposite of r s r s so these two are being

optically active and they are enantiomeric pairs so one and two these two are enantiomeric pair I will say these two are being in a tumeric Pairs and they are optically active enantiomeric pairs and instruments are always optically active so these are optically active optically active can you see optically active kids now if I draw the third one see the third one if I draw third compound just see to it everyone p o o h c h o h o h h c o o h I'll see this is also having two parallel carbons what you

can see this was not having plain oximetry this was not having plane of 70 but this compound what do you think is having plane of symmetry or it is not having plane of symmetricates do let me know is this compound having plane of symmetry or not having plane of symmetry do let me know you can see this compound is having plane of symmetry plane of symmetry is present once the plane of symmetry is present even though even though it is having two chiral carbons but because of plane of symmetry this compound can't be optically active

everyone it is having plane of symmetry so this compound is going to be optically inactive optically inactive everyone is able to understand now let me tell you some more thing when any compound is having chiral carbons and down also plane of symmetry is present such type of compound is known as meso what is meso compound a plane of symmetry or Center of symmetry is present along with chiral carbons then the compound is known as meso so let me write down this as being meso compound and let me tell you one special thing about miso it's

one chiral carbon must be r and another carbon must be S configuration I don't know which one is doing R configuration and which one is having s configuration but definitely a one Coral carbon is having s configuration then another chiral carbon must be having R configuration and let's try to find out everyone are you ready just see if I save 1 2 and LPG and arrow is moving clockwise clockwise so I will say LPG is on horizontal line horizontal line clockwise HCS this is s configuration hundred percent this will come out to be R I

am not going to write you just try to find out the lower current carbon will definitely come out to be our configuration let me show you let me show you this is one this is two CIP Rule and arrow is going anti-clockwise and LPG is on horizontal line killer science you have told me the trick everyone so horizontal line antique clockwise harendra sir so this is our configuration now it's on the first page we have gone through formula wise but formula just increases the speed formula never let us know and think what is going to

happen it's not going to teach us it's not going to visualize about the particular thing so this is everyone now let me tell you Special thing about this so these are the three Optical isomer one question must be coming to your mind that sir this is optically inactive but then also how it is Optical is so much number of questions must be coming in your brain but let me tell you these are three Optical isomers out of these three Optical isomers two are being optically active and one is optically inactive so please little bit slow

just let us know otherwise we will get confused now see everyone see if I draw this compound if I draw this compound over here just try to understand there was no too much space let me tell you over here about this compound c-o-o-h c o o h c o o h t o h o h h h so we have seen that the light one two it was going like this in which arrow this Arrow was going anti-clockwise and this arrow is coming you can see clockwise you can see very well clockwise that means this

is going over here LPG is at this place so what I should say that anti-clockwise LPG horizontal anti-clockwise this is our configuration and this is being s configuration so half portion is rotating the plane polarized light in the clockwise Direction and half is rotating anti-clockwise half portion of compound is rotating the light half ocean as rotating plain polarized light and clockwise Direction and other half is rotating in anti-clockwise Emirate another half or other half is rotating light anti-clockwise now kids if I'm playing polarized light and I am moving like this half of the portion rotated

light in the clockwise Direction and another half rotated the Light plane polarized light in the anti-clockwise direction so when I come out from the solution I entered like this plane polarized light once I am going into the solution half molecule has rotating in clockwise direction another half once again rotated like this once I coming out what others will say oh nothing has happened to the light but light will say oh you don't know I have been rotated just inside the molecule half portion has rotated me in the clockwise and another half in the anti-clockwise and

you Spectators spectator public you are saying nothing has happened you can't see have gone mad so light is talking like this gets so this is within the compound this all these things are happening just inside the compound am I right this rotation cancellation rotation cancellation is within the compound this is happening within the compound cancellation of rotation cancellation of rotation is within the compound Within and within compound means intramolecular so this is known as internal compensation that rationalization was example of external compensation but meso meso is optically inactive due to yes internal compensation that was

external compensation here it is internal compensation kids internal compensation everyone able to understand internal compensation so why meso compound is optically inactive so the reason of meso compound or meso tartaric acid to be optically inactive the reason is due to what gets let me know due to internal compensation you got it everyone got it now question arises when it is not optically active once meso tartaric acid is not optically active then why it is known as Optical isomer so kids if I say Optical isomer when I talk about Optical isomer when I am going to

talk about Optical isomers Secrets Optical isomer means Optical isomer means they have rotated the plane polarized light rotated rotated plain polarized light that's all that's it nothing more than that now if due to their rotation cancellation took place then we will say optically inactive if cancellation is not being done we'll say they are optically active so what idea we are going to get that all optically active isomers are always Optical isomers but all Optical isomers need not to be optically active and this is assertion reasoning based so what idea we are going to get gets

are you able to draw any idea about it yes we are going to understand statement what statement from this we got that all optically isomers are Optical isomers all optically active isomers are always Optical isomers but but all Optical isomers are not optically active so it may come in your assertion and reasoning it's agreed or not everyone are you agreed with this point or not yes and one more thing let me tell you let me tell you one more thing secrets suppose if God has given me hand like this hand like this without thumb and

all the fingers equal now let me know there is no thumb and all the four fingers are suppose equal now let me know is there any plane of symmetry yes if you divide it from the middle vertical plane of symmetry then both the hands will be same they will be identical then we cannot distinguish between right hand and left hand because they build with they would be they would be definitely identical and there will be yes they will be super impossible that means if a compound is having plane of symmetry let me tell you this

thing over here now see what I'm telling you first of all let me tell you if this is being meso this is being meso just see to it this is being meso compound everyone see to it o h o h c o o h this question must be coming to your brain that this is being miso compound why this is being mean so compound although it is having two parallel carbons then you will come to know that this is miso this is being miso because of plane of symmetry plane of symmetry is there in this

compound this is being plane of symmetry is over here now if you draw the mirror image of meso compound if we draw the mirror image of meso compound it's C to it a pet draw the mirror image of meso compound it will also be meso only the mirror image of miso definitely will always be miso now once the plane of symmetry is there once the plane of symmetry is circuits this is the plane of symmetry in this compound this is meso that is mean so both are being mean so so mirror image of miso is

always miso and they are not enantiomer because these two mirror images are super impossible these two mirror images of what super impossible and why they are superimposable very clear they are superimposable because they are having plane of symmetry so these two mirror images are two mirror images are super impossible super impossible impossible so they are not different because this was having plane of symmetry this is also having plane of 70 because the mirror image so these are super impossible mirror images what will you say they are identical they are not different they are being identical

identical so they will be counted as one only identical or we can say UMAS so they are counted as one because they are identical so they are not different so identical one so we can understand if any compound why it is known as meso why it is called as meso so if any compound so if any compound is having pause or cause along with chiral carbons along with current carbons so so if any compound is having pause or pause along with Karl carbons they are known as miso they are miso everyone got it so that's

why in the beginning I've told you that carbon carbon is not the necessary condition what is the necessary condition necessary condition is that the compound should not have Plato symmetry R Center of symmetry everyone is able to understand everyone it's do let me know so tartric acid whenever we talk about tartric acid tartric acid is having three Optical isomers so what are these three Optical isomers whenever the question is being asked so tartaric acid what do you write rodric acid is having three Optical isomers out three anyone is asking how tree two plus what two

plus one what are these two plus one what is this thing two plus one oh sir two being optically active two being optically active oh two being optically active do do they have name yeah so one is being text Row one is being level oh great and what is this one so this is being optically inactive this is named as meso oh these are the names dextro tactic acid levo tartric acid and meso tartric acid everybody is able to understand everyone no appima right now it they are not happy Mass gets they are not happy

mother dextro dextro tartaric acid dextro Dodge laboratory mesotric acid mesotric mesotic everyone try to understand try to understand have you got it everyone is able to understand yeah I will tell you happy must also don't worry I will let you know I will let you know so are you tired or not or full on Josh do let me know show me in the chat section chat section how's the energy level everyone I wanna say I wanna see your energy level right now how is it Josh how's the energy level everyone show me how's the Joe's

how's the energy level that's really fantastic now see now see if the compound is having odd number odd number then that is really awesome that has been asked twice in Ames two times that question has been asked in aims let me deal with that question that is really awesome see so I'm going to deal with case number two it's I'm going to deal with what I'm going to deal with case number two case number two is number two sub case b everyone ready case number two sub case b case number two case number two sub

case b this is rank deciding top 50 rank rank deciding top 50 rank otherwise you can leave it if you don't want top 50 rank now see I'm going to write one compound just try to understand c o o h c h o h C this is a question which has been asked in names I'm writing the same question exactly same question I am writing c o o h because in the examination no one will be there to let you know that it belongs to case 1 or case two you will be there only with

your brain just to decide whether it belongs to is one of his two do let me know everyone in front of you here is the case here's a question everyone do let me know this belongs to case number one or case number two just try to find out what I've told you just save afro extreme right and extreme left if from extreme right and extreme left hand side you are going to get same picture if you start moving o c o h I have seen CU at then c h o h then c h o

h and if I move from left hand side c o o x chox oh my God so I'm getting the same picture from both the side that means it belongs to case number two this belongs to case number two kids do let me know that this belongs to case number two are you getting it or not because no no one is going to tell you over there now how many caral carbons it is having how many caral carbons it is having one chiral carbon this is being one chiral carbon and this is being second chiral

carbon these two are being the chiral carbons chiral carbon this is also being chiral carbon but it's there's one thing very special this carbon is known as pseudociron what is that pseudo chiral I've heard this name pseudo Chiron have you ever heard this name or we can say Pro chiral Pro chiral prokaryotes pseudo chiral or prokaryote have you ever heard this name kits guess what yeah it's not case one case two made case too because there is symmetry whatever we are getting from the right hand side same thing we are getting from the left hand

side so it belongs to case number two everyone ready no if you don't want to go in detail if you don't want to spend your too much brain then just remember one thing I'm telling you just remember one thing what's that this type of compound this type of compound will have two optically active isomers two optically active isomers and two meso isomers meso isomers so plus two plus two how many Optical isomers will be there how many Optical isomers two plus two definitely four Optical isomers four Optical isomers that's it just cram it and you

will get full marks and those who don't want to cram it those who want to understand it those who want to understand it let me know by showing thumbs up that yes we want to understand it then I will make all these four and I will definitely let you visualize it everyone do let me know are you interested to visualize it visualize it what are these four isomers what are these four Optical isomers if yes do let me know in the chat section by showing me thumbs up now see everyone now it's not necessary that

the same example is an example could be like this see everyone the example can be given like this cn3 CH PR CH PR CH b r ch3 the example can be given like this CH Ray CH PR the center one common c l c h BR just try to understand what I am going to teach you ch3 the example can be given like this ch3 choh ch3 are you able to understand what I am going to tell you the example can be given like this also coh ch o h c h br so all they

will have same answer number of examples I have written all their answer will be same I've written first compound I've written second compound third compound fourth compound all these compounds will have same thing this is Carol that is Carol the center one is being pseudo chiral the center one is being pseudo current everyone now let me tell you how see everyone if I make this compound just try to understand c-o-o-h c h o h c o h c o h h h and c o o h now just see this compound is not having any

plane of symmetry no plane of symmetry and this compound is having chiral carbon chiral carbon and chiral carbon three chiral carbons are there all three are being chiral now you will say sir in the starting you set it is pseudo chiral in the middle one the middle one is being pseudo chiral but right now you're seeing it is being iron what just this I will let you know just try have patience my patience is burning is this entertaining like that so thank you deepti thank you deeply no see all three are being chiral this has

been chiral this has been Karan this is also been current now if I place mirror over here or we can say water image you know water image so what I mean just try to understand water image mirror downside or the river image or the ocean image ocean they do not form images so see what are you going to get h h o h c-o-o-h c-o-o-h and now o h o h and h these two are known superimposable mirror images of each other so what relationship they are having they are not having plane of symmetry no

plane of symmetry so this is also chiral carbon this is also kind of this was also in Carol so no plane of symmetry brain of symmetry is missing plane of symmetry is missing so they are being enantiomeric pair these two are being enhanced turmeric pair let me let us give the number A and B so A and B are in ensomeric pairs right and optically active definitely and isomeric pairs so optically active no these two are optically active they are not having plane of symmetry now let me draw let me draw a compound like this

C o h o h o h c o o h c o o h H H now C from where the plane of symmetry is moving from where we should divide it we should cut it imaginary plane so that I can say like yes it is involving plane of symmetry gets so if I draw one line from here if I draw one line from here you can see this is dividing the whole compound in two equal parts can you see everyone just to let me know can you see this is dividing the whole compound in

two equal parts everyone just to let me know so this is plane of symmetry this is being plane of symmetry so plane of symmetry is there this is being meso now if I see this compound in the mirror it's Mirror Image if I see this compound in the mirror it's mirror may let us say this is being C then C Dash its Mirror Image will be miso that will also be meso right so miso and miso C and C Dash what's the relationship between C and C Dash they are being identical they will be identical

isn't it they will be identical so they will be counted as only one they will be counted as only one no where is the second one B ISO from where you are going to get the second one means because I have told you in the starting two measles now see everyone tried to see to it if I draw a compound like this if I draw a compound like this everyone see to it o h o h o h c o o h and c o o h now pits do let me know is this compound

is same as C or different it's this compound same as C or different so definitely the answer will come different why difference what's the difference everyone see the difference they are all the three oh groups one upper side or its Mirror Image Lower Side all the three on same side but here 2oh are one side and one which being different side but still the plane of symmetry is existing over here what do you think plane of symmetry is present or not do let me know that plane of symmetry is being present or not gets do

let me know everyone is plane of symmetry present or not in this compound what do you think what do you say that plane of symmetry is being present or not do let me know everyone the plane of symmetry is present or not answer is yes the plane of symmetry is being present you can see very well that the plane of symmetry is present this is your plane of symmetry you can say in this this this this is your brain of symmetry can you see can you see the plane of symmetry everyone do let me know

this is plane of symmetry now in these two compounds is this is meso this is also meso are the two mesos same or different this miso and this meso are same or different definitely this meso is different from that meso and it will form Mirror Image D Dash this G and D Dash definitely they will be identical these two will be identical but these two meso are being different now the most important point that this compound is chiral and this carbon is but this is not chiral now you will say Sir whatever telling what is

saying sir we are not able to understand what's going on let's see see this is the twist you must be finding out you must be searching or must be waiting for very pseudo chiral sir what happened to you in the starting you were talking about pseudocarium prokaryon now all the four cases you have discussed now no not even taking the name of pseudo Karen what happened to you what are you talking about Sir see kids these three are chiral these three are currently but here this is Carol this is Carol Center one is not being

Carl not Carol because plane of symmetry is here this is chiral this is chiral this is not Carol it is just like it is just like if in your school you are having three friends from class one two three three friends ABC or XYZ x y z all the three friends what really friend they were real friends just like a friend in need is friend indeed but once if you have gone to Medical College X and z they are their nature is remaining same but why the friend why God turned you turn he has taken

you turn or she has taken you turn just she or he has become enemy of you during the school time you were having three friends x y z but once if you have reached to mbbs college your boyfriend X said nature is same as when you were in the school but when you have gone to the college why the friend why is nature or her nature got changed he has become she has become enemy so when you are going to write down the history what will you say about what you say about this why friend

when the school time boyfriend was friend friend close friend but once you have entered to mbbs College he was not friend he was enemy so whenever you're going to write history you will say one of friend was pseudo friend which friend if you don't want to explain to anyone you want to just tell him or her in short you will say one of my friend was pseudo friend in the history that why friend was acting as pseudo friend so in two compounds this friend has acted as chiral carbon but in these two compounds this friend

has acted as North Carolina so if I talk in the condensed formula I will say this friend is being pseudo friend everyone is able to understand or not srinath killer signs everyone do let me know that you are able to understand or not you got it or not everyone do let me know kids do let me know everybody yes now I am going to tell you difference between appimar animal dice tumor wow this example was really awesome this example is really awesome and all these examples I'm taking out time to give you all these examples

I'm always dealing with such type of cases I want to compare the chemistry with the environment with human beings so that you can easily understand it anyways let me tell you gets same but right now I am not going to tell you about animals happiness and all because one thing is left what is that R and S configuration in flying vegetables formula because we have to go we have to move one by one otherwise we will get distracted or diverted from our paths right first we were talking about types of configuration let me complete RNs

configuration then three over right through capital D capital L so one by one let me let you let me tell you each and everything thank you thank you now see so R and S configuration in flying wedge and dash formula so we are going to deal with r and S configuration and flying wedge test form line flying fetch Dash formula now what is this flying wedge and dash formula let me tell you kids let me tell you let me explain it if I take these four four atoms and this is being carbon chiral carbon and

if I say that this is one V just see tetrado if you want to visualize that throttle always make one v v for victory and this is another V this is your tetrahedral so once I have told you that fisher has seen this compound like this that two valencies are coming towards Observer side and two are being going away from Observer that two balances are coming towards of the side and two are going away from Observer now if the same structure is seen by some monkey sitting on the tree what the monkey will say yeah

two valencies are coming towards monkey side and two are going downside now this same compound now if you visualize just see everyone can you see everyone one balance is this green one is coming towards Observer side the same compound compound is same compound has not got changed only one valence is coming towards Observer side you are being The Observer just try to say that this valency is coming towards or suicide can you see the green one this is coming towards Observer side and the black one this is going away from Observer can you see kids

this black one is going away from Observer can you see and two are just in the plane of paper if I say this is the plane of board one valence is coming towards Observer side this green one is coming towards of the side the black one is going away from Observer and these two brown and blue they are in the plane of paper now this is flying vegetation formula which I have seen two valencies coming towards sub-zule side and two are going away from observe but flying based as C is compound like this that one

is coming towards Observer side this is being wedge one is going away from Observer this is being Dash and two in the pop pop means plane or paper everyone is able to understand now if I draw if I drop like best Dash formula let me write down C if I draw it like this this is being your chiral carbon one balance is coming towards Observer side towards Observer side it will look like this see it will look like this bolt it will look like bolt can you see it will look like bold because it is

coming towards Observer side something coming towards Observer side you can see it dark clear bigger let us say this is one valency that is X is coming towards of the side and one is going away from from Observer Dash means you can't be able to see it properly this is going away from Observer and two valencies are in the plane of paper are in the plane of paper can you see this is x y z and M so what picture we can withdraw from this we can say we can talk about that this is being

batch veg non veg not veg that means coming towards Observer side coming towards Observer everyone are able to understand coming towards Observer this is being dash dash means it's going away from Observer Dash is going away dash dash away from Observer away from Observer and these two are pop pop means plane of paper plane of paper these are in the plane of paper everyone but so this carbon is being chiral now it's such type of structure has been provided in the examination and they are asking just try to find out whether it is being r

or S so we have to understand the rules and regulations Selva Kumar saying I wonder why the views are less HSP word is just a million views of his pure dedication yes kids but don't worry let's move ahead with our true soul with our 100 efforts they will come when hundred thousands millions of views will be there but let's keep on trying without any division this is the thing wherever you are not getting that result for which you are deserving but then also that is the time your efforts should not be less your effort should

be hundred percent a day will definitely come your process should have that much of dedication your process must involve that Dedication that they will day has to come so you should have to have that much of efforts dedication perseverance consistency each and everything isn't it so don't worry kids don't worry definitely they will come we shall overcome we shall overcome one day my heart says see yes deep in my eye now see this is flying wedge and dash formula no just to understand its configuration RNs configuration we have to understand some rules three rules are

you ready for that rule or should I let you know one thing no need to understand rules I will let you know how to convert this compound into Fisher so if I let you know how to convert flying Bell staffs into Fisher then we know very well the official projection to we know very well so let's understand how to convert flying West Dash into Fisher so it's rules for rules for converting flying based Dash to Fisher it's very simple let me tell you it's very simple it's not tough it's it's not tough it's very simple

see rule number one first of all let me draw let me draw some compound let me write down here is carbon here is carbon here is iodine here is bromine here is hydrogen here is chlorine right so let me explain this is being Fisher and that has been flying best as first of all we have to understand this is being flying by stash and this is being Fisher now first rule whatever the atom is attached atom or group attached to dash line do remember any atom or group which is attached to dashed line just put

it on vertical line put it on vertical line rule number one let me write down rule number one any atom or group attached to Dash line keep it on vertical line either at top or at bottom at top or at bottom that's your choice top or bottom that's your choice that's your choice this is the rule number one are you able to understand can you see what I have written so this bromine is on dash line I kept this bromine over here I kept bromine over here this what you can understand everyone do let me

know can you understand this much so this bromine was attached on dash line I have kept over there now cap keep all rest of other atoms as such keep rest of other atoms as such no worry is nothing to do anything else hydrogen is over here I kept hydrogen over here chlorine is over here I kept chlorine over here now iodine is over here there is no place so iodine are kept at this place everyone able to understand are you able to understand just take care of atom which is attached to the dashed line you

have to keep it on the vertical line rest of atoms as such rest of atoms as such you got it so what is the configuration of this compound do let me know what is the configuration of this compound one two arrow is moving one two arrow is moving kids you can see arrow is going anti-clockwise and least priority group is over here so what you are going to say what will you say kids LPG is on horizontal line anti-clockwise arrangea r configuration so this is also our configuration everyone able to understand this one is also

our configuration so everyone is able to understand how to convert flying best Dash into Fisher let me give you one example now you will say sir what is happening if I keep this over here or this over there what is going to happen now let me tell you some special rules so that you will get more confidence gets are ready for a special case special case they are going to boost your intelligence CC special cases then you can do within the air you can do this compound in the air no rule is required you can

do in the air spatial three cases three special cases my configuration of the compound does not change configuration of compound doesn't change configuration of compound does not change if you are able to understand this thing these three spatial cases by configuration by which configuration of the compound is not going to get changed then definitely your life is going to become like wow wow wow life so is everyone everyone ready let me drink water keep yourself hydrated everyone everyone keep yourself hydrated so are you ready do let me know that is so we are ready kids

do let me know is everyone ready say yes how's the Josh no see three special cases by which configuration of compound does not change case number one C to it is number one why rotating the whole compound by 360 degree in the plane of paper 360 so it's simple how it is going to get changed it will come over there only right by rotating the whole compound by 180 degree 180 degree configuration of the compound will not change now you will say sir prove it prove it everyone needs proof isn't it so just prove it

by simply writing we are not going to follow just explain it so get C if I write down this compound foreign clh what is the configuration of this compound do let me know what is the configuration of this compound number one number two number three number four LPG not you must have become Pro of it so arrow is going clockwise Direction now LPG is on vertical line clockwise we see what should I write VC yes what should I write VC everyone do let me know we see complete it oh my God you are taking this

much of time b c what should I write very clear Road where is killer science killer science is there or not I don't think clear science is there otherwise I must have got the answer oh clear science is there now what I said you took too much time clear Science Why this system made by you only now very clear route now if I'm rotating the whole compound one by 180 degree C 180 degree if I am going to rotate this will come east will become West West will become East North will become South South will

become now see just try to understand who is going to what h we are I CL Now find out what's the answer number one number two number three arrow is going to drink clockwise show RPG is on vertical lines so vertical line clockwise R this is also R configuration so she gets what I have told you by rotating the whole compound by 180 degree the configuration is not going to get changed now what does it indicate it indicates that if you rotate the compound by 90 degree then R will become S and S will become

R they will be the enantiomeric pair if you rotate the whole compound by 180 degree they will remain identical so what's the relationship in between this compound and that compound if anyone is going to ask what is the relationship in between these two compounds so definitely these two compounds are identical they are homomers they are neither diastomer nor enhanced human so this was the first compound if you rotate the whole compound by 180 degree configuration is not going to get changed gets everyone is able to understand oh sleepy mood oh my God clear science so

I think it's going to be 11. it's do let me know let me tell you some points then I I think I have to take the one more lecture for optical isomin because it's a very um big topic so let me tell you these rules three rules then I will end this class okay gets do let me know oh my God so less likes you're not liking the lecture smash the like button if I'm not saying anything then you are also not hitting the likes hit the like buttons sir in previous slide you gave chlorine

as LPG no no no let me see let me check it out chlorine can't be LPG weight oh sorry sorry sorry sorry sorry yes yes yes I think it gone wrong see it got wrong yes thank you thank you Shiva Kumar yes see by chance to LPG chlorine I have written sorry so chlorine is not LPG hydrogen is LPG I take my stylus back I take my words back Secrets it's wrong how chlorine can be LPG Shiva Kumar thank you thank you see it's a slip off stylus slip of marker hydrogen is LPG gets hydrogen

is being LPG chlorine can't beat the lpgs so I think the configuration will get change configuration will also get changed because hydrogen is LPG so let me just stay to it everyone LPG is hydrogen because this is having the least atomic number one atomic number right so Arrow was going anti-clockwise right so let me write down arrow was anti-going I'm going this hydrogen is least priority group is on vertical line arrow is going anti-clockwise so V A just completed everyone and Shiva Kumar thank you VA what should I write v a very awesome subject very

awesome subject so it is s configuration C gets s so by chance here I have written the least priority group that was by chance so this is s configuration s configuration right kids right everyone right so see just a little slip of marker that I have written here LPG at place of chlorine hydrogen is the LPG gets just show me the thumbs up so that I can understand that is you have Rectify rectified the this problem or doubt or the misprinting or error whatever you want to say you can say you got it everyone no

and thank you Shiva Kumar for reminding me so everyone till now now special case number two let's deal with case number two case number two not spatial process number two better to say not the case these are the processes so in place of case let me write down process gratitudes right otherwise we will get confused so let me write down here process number one process number two this is process process because we are just changing to process number one and here now process number two process number two now process number two by making even number

of exchanges this you must have studied somewhere by making even number of exchanges just see by making even number of exchanges configuration will not get changed configuration once again will not get changed now see the same case I am taking iodine bromine CL hydrogen its configuration though we know very well that Arrow was moving clockwise and least priority group on vertical line LPG so we stay very clear Road R configuration now how to do it even number of exchanges just C to it let me draw the plus sign visual projection okay now see if I'm

exchanging this with this this is one exchange then I am supposed to exchange this with this what I will get hydrogen over here chlorine at this place iodine at this place and bromine at this place now some kids must be thinking so why you have exchange these and these only you can do like this also you could have done like that okay let me take one more example in that let me exchange this with this bromine and cl okay bromine with cl then this is one actually and then I'm supposed to exchange this with this

bromine CL bromine at this place CL at this place and hydrogen at this place and iodine at this place if all the three are not having same configuration if all the three configuration are not coming same that means I have done something wrong I'm teaching you wrong okay so let's see this is also my examination or you can say whatever the thing right let's check it out gets so you see to it if I say this is number one this is number two arrow is moving like this and this is being anti-clockwise you know clockwise

and tick clockwise at least priority group is over here so horizontal horizontal anti-clockwise again sir our configuration so we got R this was our this was R yes our configuration that is also our noun let me check it over here one two three arrow is moving this is clockwise or anti-clockwise anti-clockwise anti-clockwise the least priority group is over here you can say h a r i mean sir R qualification everyone is able to understand or not do let me know kids from all the ways it is coming same I've told you why moving it 180

degree configuration is not getting changed by making even number of exchanges configuration is not getting changed now mind-blowing third process I am going to let you know see that is really mind-blowing and that will blow your mind blow your mind now see and this is har Harin sir and blah blah blah very clear Road thanks once again to killer science that he is really helping a lot he is full energetic strength and arrest of other sweets are also very very energetic but today definitely he has helped a lot so in today's session he holds a

whole lot of weightage yeah isn't it so now see process number three process number three by holding anyone process number three says by holding anyone and rotating other three what is this by holding anyone and rotating other three configuration will not get changed configuration will not get changed now how to hold and how to rotate that is the super awesome thing by holding anyone and rotating other three clockwise or anti-clockwise so answer is either clockwise or anti-clockwise clockwise or anti-clockwise this is really awesome if you are able to understand this then you can do all

the questions within fraction of seconds this is really going to change your life now see let me write down the same compound the same compound is like this I br tlh now kids I will ask to you only and you are the one who is going to tell me to which compound should I hold and which compound should I rotate everyone is going to get chance so I will ask to three students okay I will make three compounds I'm going to make three compounds don't worry everyone is going to get Chance one compound second compound

third compound so everyone is going to get Chance gets at least three compounds I have written first chance I am going to give killer signs killer signs you got the first chance the first compound just let me know out of these four which atom should I hold you got the first chance hold which atom should I hold let me write down one two three arrow is going clockwise and this was vertical clockwise VCR very clear Road R configuration so do let me know old bromine so old bromine bromine is on hold so bromine will remain

over here right because bromine is on hold so other atoms should I rotate clockwise or anti-clockwise do let me know tailored science do let me know should I rotate other atoms clockwise or anti-clockwise clockwise or anti-clockwise upholded bromine other atoms should I rotate clockwise or anti-clockwise anti-clockwise same and rotate and take clockwise now if I am rotating anti-clockwise you want chlorine on the East position or South by rotating chlorine you want to make chlorine should come on the best position or South position you want chlorine to come on the best position or South position do

let me know where you want this chlorine should come do let me know and take clockwise I am going to rotate it anti-clockwise you want that this chlorine should come on the west position or the South position out okay once I am rotating this chlorine definitely in front of chlorine this is on hold iodine must be moving and then hydrogen must be moving so chlorine he wants at the South position so chlorine has come over here just in front of chlorine iodine so ahead of chlorine iodine and just in front of iodine hydrogen is moving

it's you are able to understand are you able to understand how I have rotated so suppose if I am rotating this is I am holding the stylus and there the remote if I'm rotating like this so it will move like this if if the stylus is moving my head is moving this Mark this remote must be moving and if I'm moving like this so it everything was must be moving in the same direction and whatever they want to be following each other no secrets let's see what is the configuration of this compound configuration of this

compound number one to iodine number two bromine and arrow is going which direction this is anti-clockwise Direction and this is over here LPG is on horizontal line h a r current we have got R configuration now second second chances given to vidharjunani with with you want to hold you want to hold with Chatham with just to let me know you want to hold the Chatham fast fast you want to hold which atom do let me know which atom you want to hold which atom you want to hold chlorine so chlorine is on hold so hold

chlorine so chlorine now rest of other atoms you want to rotate in clockwise direction or anti-clockwise Direction rotate clockwise direction or anti-clockwise Direction which direction you want which direction clockwise so you wanna rotate clockwise so if you are rotating clockwise this bromine you want at South or this bromine you want it uh best position so while moving to bromine you want bromine you want at South position or at best position do let me know where you want this bromine bromine should come to the South position of West West okay so I am moving this is

on hold bromine once the bromine is coming over there that's ahead of brominees hydrogen will come over here and this iodine will come over here right one one position so iodine will come over here no let's find out what is the configuration of this compound just see number one this number two this so one to two I cannot come like this I should come like this because while coming from one to two we cannot cross the third highest priority group we can cross only LPG this point I have told you so this arrow is moving

anti-clockwise you can see anti-clockwise and this is LPG horizontal anti-clockwise surrender R configuration so you got the same on circuits you got the same answer everyone no is there anyone who want to rotate who want to rotate it is there anyone now anyone want to rotate it so is there anyone so everyone got it everyone got it gets so this is your homework you can do it yourself you can do it yourself so now the toughest question based on this I'm going to give you and then I will end this class otherwise because uh we

are not able to complete it in one lecture I will take second lecture of optical isomerism so let me give you that question which has been asked that question which has been asked in aims so see what question has been asked see this question was asked find out the relation C this is being a compound one is being B compound everyone C to it A and B foreign this is being your B compound so the question was A and B r first option enantiomers second option diastoomers three option identical the option none what's the answer

everyone do let me know what's the answer killer science is going for C and waiting for rest of others what answer they are going to give just let me know let me try the previous slide last case okay after this after this question definitely I will move to that don't worry definitely I will move to that but first of all because everyone is indulge in this question let's complete this question and definitely after completing this question getting the answer of this question we will move back B some are going for B some are going for

C so it's you want to do it fast or you want to move slowly just like turtles you want to move like rabbit fast or you want to move like turtles which way would you like to move do let me know then I will let you know the answer kids fast see rotate it by 180 degree rotating by 180 degree rotate it by 180 degree rotate Rotation by 180 degree see when you are going to rotate it by 180 degree this will go up just in front of this bromine will come in front of this

chlorine will come in front of this qualification will not get changed this is the answer do the rotation by 180 degree configuration will not change now those who don't know those who don't know this rule they will do yrs system they will do it by RS system now the one who is going to do it the one who is going to deal with RS system C how they are getting failed just do let me know what is the configuration of this chiral carbon red carbon everyone try to find out what is the configuration of this

red carbon and do let me know what is the configuration of this red carbon let me check it out how many of you are getting failed how many of you are going to get fail over here let me know the red carbons configuration I'm waiting for your answer definitely 40 to 50 percent gets will get wrong answer I'm waiting for your answer everyone do let me know get CS do let me know what's answer you're taking too much time quick quick r with is getting r let me check it out first five students also what

also they are going to get our killer science is getting our two strengths they have got the same answer are Rajkumar is getting our three students they've got our let me see one more strength I'm waiting for one more answer okay so four answers I've got now check everyone check whether your answer is being right or wrong are you damn sure that your answer is right see check it out everyone say to it definitely this carbon is attached with chlorine so chlorine will get number one now this C this is carbon and the lower one

is also carbon so there is time this is definitely LPG group so in between these two carbons there is time this is carbon this is also carbon now if highest atomic number oxy and oxygen and its highest group is bromine who is senior who is having more atomic number do let me know this oxygen is going to we have more atomic number of bromine gets do let me know these two carbons there is time because this red one is attached with this red one is attached with one you you free oh these are the four

atoms this is LPG this is senior this carbon and this carbon there's tie who is going bromine is going to get number two so once the bromine has got number two kids so one and two the arrow is moving which direction arrow is moving clockwise Direction and LPG is on horizontal line h clockwise Direction s configuration so this carbon is having s configuration everyone got failed everyone got failed or not yet do let me know that everyone got failed you have seen coh and you have given number two to CH never see the group this

is not IUPAC nomenclature kids this is not IUPAC nomenclature this is being your CIP rule don't apply IUPAC apply kids apply CIP Rule and CIP rule says move atom by atom don't see the group don't go and see the bigger group just move atom by atom everyone got failed or not ah yeah carbon is having double bond so what double bond although the this carbon is attached with three oxygen three oxygen but we have not to see all the atoms we have to the senior most one atom we have to see the senior boost one

atom and this is having senior most one atom that is having three oxygen but we are not interested in three oxygens this is decided by bromine only once this bromine is the highest atomic number carbon carbon same but bromine it is winner by bromine killer signs you got it or not everyone you got it no everyone got filled I said only 40 to 50 percent students are going to get failed but everyone got failed gets now if you are going to do it by RS system you won't be able to do it you won't be

able to do it because you are going to get you are going to take too much time and even you are doing wrong approach everyone everyone you got it now let's move so answer is they are identical they are being identical identical is the correct answer I hope that everyone is able to understand now let's move at the back one and Shiva Kumar is going to do it Shiva Kumar okay let me know which atom you want to hold Shiva Kumar do let me know which atom you want to hold fast do let me know

Shiva Kumar where is Shiva Kumar which atom you want to hold which atom you want to hold do let me know hold I'm waiting for you answer Shiva Kumar old iodine Shiva Kumar folded iodine now rest of other atoms you want to rotate clockwise or anti-clockwise clockwise or anti-clockwise rest of other atoms you want to rotate clockwise or anti-clockwise Shiva Kumar clockwise so you want to rotate clockwise you want to make bromine bromine or chlorine which position either bromine or chlorine you select either of atoms and which position you want to they should come and

take position which position you want to make them located bromine should come east position or South position do let me know where you want this bromine should come where you want that bromine should come or chlorine should come whatever the atom you can select and do let me know where they should come East bromine should come at East okay bromine little bit he has shifted bromine over here so chlorine over here now hydrogen should occupy this position but already this is being occupied so hydrogen will come over here hydrogen will come and occupy this position

now see Shiva Kumar number one I will give to iodine number two to this and I can move from LPG only so arrow is moving clockwise arrow is moving clockwise so LPG is on vertical line vertical line clockwise we see very clear Road our configuration r so Shiva Kumar are you able to understand everyone gets so everyone got it everyone is able to understand it do let me know that yes you are able to understand you got it now definitely today's session was mind-blowing and really you kids are super awesome that for the continuous five

and a half hours it's 18 past 11. almost half past 11 you can say five and a half hours for The Continuous five and a half hours you are studying you're watching this lecture really awesome really awesome I would like to say from the internal core of my heart really you are dedicated students hard-working students and once these kids are really hard working your success is waiting because there is no substitute of hard work and this not only the hard work it requires perseverance it requires persistence and it requires a high willpower you know that

the kids with high willpower no obstacle is there and no obstacle can stop a person with high willpower you are going to get your aim you are going to reach your goal success is definitely waiting for your kids all the waste all the best all the best kids best of luck Jai Hind I matram all the best so I was thinking of giving you one question for your homework but I think it's too late already you must be tired so should I give you one question for your homework let me give you one question for

your homework okay just one question for your homework this is your compound foreign derivative you are supposed to find out total number of chiral carbons this is somewhat you can say cholesterol derivative this is just for practice this is just for practice okay this is your homework let me tell you this is your homework okay kids I would like I would like to see the answer in your comment section five good night kids really dedicated strengths all dedicated students all future doctors really all the best bye bye from your HSP Baba buy it from your

conquer team I'll be waiting yes definitely in the coming lecture okay bye foreign foreign foreign